Rank of a matrix

Lec-03 Rank of a matrix

[bepawsitiv]

Your way of explaining is great sir, thanks sir from all students

[rahulraaz]

Sir, at 24:50 in the second question we can also say that the top most vector i.e; (2, 2, 3) is a linearly dependent on 2nd row vector.. Because if we multiply with -1 in second row then we'll obtain first row. So how can we say there's one linearly independent vector?

[komal]

Lecture 4 ( solution of linear equation 1 ) is missing.

[purandarroy]

At 24:42 for matrix "B" It has been told that 2nd and 3rd row are dependent on 1st row.So it is the only independent row. But we see that we will get 1st and 3rd row by multiplying 2nd row by -1 and -3 respectively. Similarly we will get 1st and 2nd row by multiplying 3rd row by 1/3 and -1/3 respectively. Hence, each rows are dependent of remaining two rows. So how can we say that the no. Of independent rows=1?? Plz sir, help me by clearing my doubt 🙏

[nancytripathi]

From where I can get the assignments of this course

[mohammadidreesbhat]

abrupt shift from echleon form to this concept.

[surajmg]

I search for rank of matrix but i am getting videos from some unqualified bihari hindi lecturers which dont expain the concepts like this lectures

[bedbyashkhadagray]

There are much more inequalities of rank which isn't mentioned in this vdo