8. Proving the Limit of a Composite Function

preview_player
Показать описание
Here we essentially prove that a limit within a limit can exist in the same way that a function within a function can exist and this limit is important as it is the basis for proving other limits as well.
Рекомендации по теме
Комментарии
Автор

I reviewed a lot of sources and I'm glad I didn't give up, because I finally found your video and your explanation was exactly I exactly what I was looking for. Thus, all the searching was worth it. Thank you very much. I'll leave my Like and subscribe.

yzhjzgx
Автор

That was the only proof that got through to me! nice work!

cocoa
Автор

This is soooo clear. Thank you so much for your narration!

jingbinyu
Автор

Thank you. I had a doubt about the choice of delta_1 for epsilon which you specifically helped out with.

seekerm
Автор

Thanks for the proof. This could be generalized to the case where f is not necessarily continuous at u=L (in this video, we are implicitly assuming that f is continuous at u = L, as we are being told that lim f(u) = f(L) as u->L). But if we simply say that lim f(u) as u->L = F, even then it should be provable, using similar argument as made in the video, that lim f(g(x)) = F as x -> c

santoshbanerjee
Автор

Hey, this was a helpful proof. However I'd recommend slowing down at the end, where there are several logical implications to chain together, it's the trickiest part.

urthogie
Автор

sir please translate your every vedio in hindi

bhavishyapandey