Find an antiderivative by the method of inspection |Integrals Ex: 7.1| NCERT Solutions| anandlessons

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NCERT Class 12 Mathematics Part 2 integrals Ex 7.1. Find an antiderivative(Intergral) of following functions by the method of inspection.

Learn how to find an antiderivative by the method of inspection

Timestamp
(0:00 - 0:44) - Intro
(0:45 - 4:17) - antiderivative of Sin2x
(4:18 - 6:20) - antiderivative of Cos3x
(6:21 - 8:33) - antiderivative of e^2x
(8:34 - 16:36) - antiderivative of (ax + b)^2
(16:36 - 21:32) - antiderivative of Sin2x -4e^3x

#Class12 #ncertsolutions #integration #anandlessons
  1. Anand Lessons
  2. Sin2x
  3. cos3x
  4. e^2x
  5. (ax b)^2
  6. Sin2x -4e^3x
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Комментарии
Автор

Sorry for the inconvenience students. In question 4 while writing the final answer I wrote 2abx instead of abx². It should be abx². So, the answer will be
(a²x²)/3 +b²x +abx²

anandlessons
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Thankyou so muchh bro for your explanation

thenikhiljat
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Pls sir make more videos you explain great♥️

Mamtakumari-cctq
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Sir cos x=-sinx hote he
To apne jo 2nd sum sumjaeya usme negative sign kho ni he ?

amanjotkaur
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inspection methode ko explain toh kr dete sir concept bta dete inspection methode ka

SGOD
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Sir vo abx² h 2abx nhi 😳4th question m

Focuss
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Sir first solution of 4th Q. 's ans at end abx^2 or 2abx^2 have.. ?? 🤔

RajKumar-gqyn
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Nahi mtlb ye samjh nahi aya sir ki "maine upper kiya hi hai " upper kiya hai to kya hua app fir se repeat karo

stereodynamicgaming