Pythagorean Identities Visualized #shorts

[ismailshtewi]

This identity is Pythagoras bound inside a circle.

[Davidrodriguez-vbzk]

Earned a follow! I love seeing new ways of the same old stuff

[Necione]

Damn wtf I actually scrolled to this the moment my parents walked in. Keep up the good content 👍👍

[abist]

make a right triangle so that the hypotenuse=H
adjacent side would be Hcosθ
opposite side would be Hsinθ
Pythagorean theorem- a²+b²=c²
(Hcosθ)²+(Hsinθ)²=H²
H²cos²θ+H²sin²θ=H²
cos²θ+sin²θ=1

[Axiom]

Never seen this before. Really cool :)

[aditya.khapre]

But turning the sin²x 'upside down' made it a cos²x graph.

[deltasingh]

Only if teacher at school could explain this

[nechiii-]

😂mind blown every time
- Yes no one taught us like this

[Silver_G]

Hyperbolic counterpart of this identity please

[froyocrew]

unit circle pythagorean theorem way better demonstration imo

[pro_faitex___]

Функция cos и sin это следствие такого равенства

[DyNovalis]

the area that is represented here doesn't equal 1 though, so how is that area relevant? flipping the sine² changes the curve from a sine² to a cosine², which does indeed result in the same area as the original cosine². The reason sin² x + cos² x = 1 is that both functions are bound between 1 and 0, have the same shape as each other and are offset by half a period, which means each of the curves that moves from 0 to 1 will reflect the same rate of change from 1 to 0 in its partner function. Its nothing special about a sine or cosine its a result of how functions with these parameters work.

[phanitejasrimushnam]

Can you please tell me what software you are using

[hmasamuneeric]

Just use the Pythagorean Theorem to prove

[lydwac]

i came a little as u moved down the sin

[soulswordobrigadosegostar]

oh dear God, this was so satisfying...
shit, give this a bigger age rating, this ain't suitable for children

[lol-hokj]

sin(x)=b/c cos(x)=a/c
∵a^(2)+b^(2)=c^(2)_(@)
∴Let *
∴(a^2+b^2)/c^2_(@)😅
∴