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Solving a finite number problem using infinities

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Here's a problem about sequences of finite (natural) numbers, subject to a simple finite rule, and all of these sequences have finite length... but we can't use the elementary language of finite numbers to prove this!
Recommended prerequisite:
Addenda:
(4:07) This argument might seem like a complete proof, but it's incomplete! Pure base expansions of a number can have incredibly recursive structure, which makes the intuition difficult to formalise without something with comparable expressive strength to ordinals. Consider: how do we measure the "complexity" of the shape of a base expansion, so that this "complexity" strictly decreases? Given the arbitrary nesting of these expansions in general, how do we know that a descending sequence of "complexity" must inevitably reach the shape for 0 in *finitely* many steps?
(11:24) That every descending sequence of ordinals is necessarily finite follows immediately from how ordinals are well-ordered. The demonstration in the video was an attempt to make it more believable (success in that matter is questionable).
(9:31) Please pay no mind to the number line. (Thanks @pudy2487.)
__________
Timestamps:
00:00 - Introduction
02:35 - Defining the sequence's rule
03:45 - Proof idea
04:43 - Overview on ordinals
05:51 - Using ordinals to describe "shape"
06:31 - The ordinal "shapes" decrease!
08:42 - Ordinals are well-founded
09:06 - Finite example
09:30 - First infinite example
10:06 - A bigger infinite example
11:22 - General case
12:06 - Putting it all together
12:32 - Loose ends
13:08 - Thx 4 watching
Recommended prerequisite:
Addenda:
(4:07) This argument might seem like a complete proof, but it's incomplete! Pure base expansions of a number can have incredibly recursive structure, which makes the intuition difficult to formalise without something with comparable expressive strength to ordinals. Consider: how do we measure the "complexity" of the shape of a base expansion, so that this "complexity" strictly decreases? Given the arbitrary nesting of these expansions in general, how do we know that a descending sequence of "complexity" must inevitably reach the shape for 0 in *finitely* many steps?
(11:24) That every descending sequence of ordinals is necessarily finite follows immediately from how ordinals are well-ordered. The demonstration in the video was an attempt to make it more believable (success in that matter is questionable).
(9:31) Please pay no mind to the number line. (Thanks @pudy2487.)
__________
Timestamps:
00:00 - Introduction
02:35 - Defining the sequence's rule
03:45 - Proof idea
04:43 - Overview on ordinals
05:51 - Using ordinals to describe "shape"
06:31 - The ordinal "shapes" decrease!
08:42 - Ordinals are well-founded
09:06 - Finite example
09:30 - First infinite example
10:06 - A bigger infinite example
11:22 - General case
12:06 - Putting it all together
12:32 - Loose ends
13:08 - Thx 4 watching
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