Probability of Consecutive Coin Flips

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He doesn't mean it's 50% in both multiplication of 1/2 but it's another 50% of getting the chance heads since you have to repeat it 4 times

driveincrystals
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Thanks this helped with my grade 1 math question

iiOmen
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Why do people like this save my life before an assessment 😂❤

Turtle-umgl
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The reason why these can be tricky are the questions themselves. They could word it something like, “If you flip a coin 50 times, landing on heads 49 times, what is the probability of getting heads on the 50th flip?”

In that case, the answer is 1/2 because the question asks for the probability of a single flip, and the probability of a coin doesn’t change.

smrtvillager
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Thanks fort he video.
30/08/2024 Friday 11:28PM

Nileshpandey
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This is how our teachers should teach, it's much easier 😊

Lowkeychristian
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Thanks so much! This help me in my math problem in grade 5

TheRealKaito_
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To be completely ckear this question should say only flipping it four times.

The odds reduce based on the number of flips.

For instance if you flipped 100 times the odds are significantly lower than 1/16 of getting 4 in a row.

zanussidish
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Just find sample space and its one outcome from the sample space. Do number of outcomes to the power of the stages. 2 outcomes(heads&tails) to the power of 4th stage(coin is flipped 4 times)= 16 possible outcomes. Out of those 16 outcomes, one outcome in the sample space will have {hhhh}, so the answer is 1/16

hejjo
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I used pascals triangle. The fourth row is 1-4-6-4-1. This also tells you the possibility of all other outcomes.

fishjj
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If you imagine hard enough, you would start to think that getting head 4 times in a row on coin tossing is hard😅

Just_Panpans
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i have the brain of a child 😂 i laughed so hard at this question

Rayydude
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Very good brother upload another videos

hiteshmotiyani
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Had a similar question in a test: Probability for same side coin toss 3 times in a row.

jackojb
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idk how that works because i forgor so i just do 1(0.5)^4 and it works just fine

Henry-kdmu
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Idk if this method works in regards to this question or any of a similar nature but what i've figured is to multiply the amount of times you flip to the amount of heads needed for the statement. Since they'd both be 4, it would result in 4x4 =16 and as a result there's a 1/16 chance of achieving the event. Could be seen as 1/4 chance of getting a head and another 1/4 chance of getting four heads in a row.

Tenebris
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You made me understand in 2 minutes. ❤

realtimestatus
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Nah man its 50/50 cause you either will or you wont simple 👌🏼

averystevens
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It didn’t mention how many flips. What if it can flip infinity times? What will the probability be?

porridge
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P(X=k)=nCk×p^k×(1-p) ^(n-1) formula of BINOMIAL PROBABILITY
For consecutive heads

Simplify it then you will get 0.5^4
;) took me around 37 seconds to solve also note this formula it is very important 😅

girishchandrasrivastavathA