Calculus II: Work (Full lecture)

Using the definite integral to calculate work. I think of work problems in two types: slicing and scooting.
You can jump to scooting here: 40:13

[georgesadler]

Professor Hower, thank for an outstanding video/lecture on Work Problems in Calculus Two. I am familiar with this topic from Engineering Physics One, Statics and Dynamics. Setting up Work Problems is highly problematic. From experience with Work/Word problems, I found that it is easy to make errors. Professor Hower, at the 58:58 minute mark in the video when you integrate 32 minus 1/10 y dy from zero to 100, which is equal to 32y - y squared/100, you are missing the evaluation line, which contains the numbers zero to 100. Please correct this error in the video.

[zwithgol]

At 16:26 you say the distance traveled is 50-y. I've seen many other videos where they say that distance is just y. I understand that it's due to whether you count y from the top or the bottom and it seems you are starting from the bottom???? If you were to start at the top how would the set up change because there is a big difference between y and 50-y?