Electricity Class 10 Sprint X 2020 | CBSE Physics | Science Chapter 12 | NCERT @Vedantu9_10

Abhishek Sir will teach you to prepare for CBSE Board Exam 2020. Learn the concepts of the Resistance, Conductors, Resistivity, Circuit, Circuit Diagram, Ohm, Ammeter, Voltmeter, Voltage, Current, Resistors, Potential Difference, Battery, Filament, Electric Charge, Bulb, Watt, Electric Circuit, Electric Charge, Electric Current And Electric Potential Or Potential Difference. This will help you to prepare for the CBSE 2020 Board Exam.

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In today's video, Abhishek Sir will teach you to prepare for CBSE Board Exam 2020. Abhishek Sir will go through all the relevant Formulas of the Class 10 Science Chapter 10-"Electricity" with proper explanation. This will help you to prepare for the CBSE 2020 Board Exam.

Current Electricity, Electric Charge, Electric Current, Potential Difference, Resistance, Resistivity, Combination Of Resistance, Resistance In Parallel And Series, Ohm's Law, Electric Power, Heating Effect Of Electric Current, Joules Law Of Heating, How Metal Conduct Electricity

#electricity #physicsclass10 #vedantuclass10

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Electricity Class 10 Numericals | Class 10 Physics Electricity Sprint X | Class 10 Physics Chapter 1 | Class 10 Electricity | Electricity Numericals | Electricity Full Chapter Class 10 CBSE | Electric Current | Abhishek Sir Vedantu | Electricity | Electricity Vedantu | Electricity Class 10 CBSE | Electricity Class 10 Vedantu | Physics Class 10 Formulas | Electricity Class X CBSE | Current Electricity | NCERT Solution

[devkisahu]

First case:
P-100 W
V-220 V
P=V^2/R
P=220×220/100 =484ohm

Second case:
P=60W
V=220V
P=220×220/60=806.66ohm

So 60 watt bulb has more resistance

[bibhansupanda]

Bulb having 60 W has more resistance .(Since, P=v^2/R)

[sunilkumarg]

Home work ans:-
P 1 =100 W
V 1=220V
R =V^2/P =220*220/100 = 22*22 =484 ohms
P 2=60 W
V 2 = 220 V
ohms

Therefore, the bulb with 60W and 220V has higher resistance

[Monika-byvc]

Ans is 60 Watt bulb operating at 220 V will have more resistance because power power is inversely proportional to resistance so if power is less then resistance will be greater. Thanks sir.

[tanaykumar]

Sir a bow down to you!!!

Your energy during the session reflects your passion towards your work which moulds your teaching skill in the graetest and in its best way

[kartikbhardwaj]

Sir, I did the second question in just 5 seconds since b has more length and less area compared to other figures.

[girendrapathak]

Hw, 100w bulb has more resistance because current of 100w bulb has consume more current of 2.2A . Whereas in 60w bulb current is1.5A .

[udaygarg]

Sir you are the best teacher in the world ☺️

[shweta_]

Given:-
Power of one bulb(P1)-100W
Power of another bulb(P2)-60W
Potential difference (V)-220V
Now, when P1=100W.
R1=V2/R
=220×220/100
=484 ohm
Again, when P2=60W.
R2= 220×220/60
=806.6 ohm
Hence, Resistance of bulb having power 60W is higher than other.
THANKYOU❤ BALLE - BALLE💫

[passtime]

HW ans 60W

P=V^2/R
60 = 48400/R
R=48400/60
R=806.667

[udaygarg]

why are the people disliking such a good lecture

[BrijeshYadav-ronf]

P=v²/r
In first case,
100=220*220/R
R=484 ohm
In second
R=220*220/60
R=806.67 ohm
So, bulb 60watt contain more register.

[nishitsethia]

H.W :-
R1 =V square /P1

R2 = V square/P2
Since P1>P2 (100>60)
Hence, R2>R1
Bulb with 60 W has more resistance..

[AlokSingh-huho]

Sir apki team or aap log kitne Achhe hai jo ham sab bacho ke liye free classes provide kar rahe hai aisa koi bhi enstitute nahi hai jo free classes de
Vedantu is great Institute in world 🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂🙂

[soumyaranjandas]

Given,
R1=100 ohm
R2=60 ohm
V=220 v
Case-1 By ohms law
I1=V/R1
=220/100
=2.2 A
Similarly, Case-2
I2=V/R2
=220/60
=3.66 A
Therefore 100 watts bulb draws
less resistance because current is less flowing.Thank you sir.

[c.p.sharma]

Lakhon log jab kehte hai "rehne do yaar"
Tab koi ek kehta hai tu Kar.
Hamari physics ki naav to doob hi gayi thhi
Kisi ne bachaya humein wo aap ho sir.

[sudeepadas]

Homework :
Answer is the bulb with power 60Watt
Explanation:
Power=V×I=V^2/R
More power then less resistance
Less power then more resistance
So the bulb with less power has more resistance.
Hope you like it😃

[reenagupta]

Since P is inversely proportional so 60W bulb has more resistance.

[aman_neet]

Homework answer.

By using formula P=V^2/P
For 100watt bulb
R=V^2/P.
R= 220*220/100.
R=484 oms

For 60watt bulb
R=220*220/60
R=806.666

Therefore 60watt bulb has more resistence than 100watt bulb

😊😊😊😊😊

[deveshnagre]

homework question

the answer is using formula P =v^2/R. so for 100watt the resistance is 484. now for 60watt we have resistance 806.6. so 60Watt bulb have more resistance