filmov
tv
Find d2y/dx2 when x = asin^3t , y = acos^t.
Показать описание
Bsc Maths successive differentiation answers | Differential Calculus| Lucknow University Semester 1 | #bscmaths #enginnering #maths
0:12:16
Implicit Differentiation - Find The First & Second Derivatives
0:09:20
Second Derivative using IMPLICIT DIFFERENTIATION (Worked Example)
0:06:11
derivative notations d/dx, dy/dx, and d^2y/dx^2
0:02:53
Find first and second derivative for x = t^2 -3t, y = t^3 in terms of t. Parametric equations
0:03:41
Find the Second Derivative using Implicit Differentiation with the Unit Circle x^2 + y^2 = 1
0:00:13
Find d2y/dx2 when x = asin^3t , y = acos^t.
0:14:34
Implicit Differentiation
0:00:48
Solve d2y/dx2=0
0:02:21
If e^y(x+1) =1, show that d^2y/dx^2 = (dy/dx)^2 Ncert continuity and differentiation second order
0:02:26
Second derivatives | Advanced derivatives | AP Calculus AB | Khan Academy
0:06:29
Second derivatives (parametric functions) | Advanced derivatives | AP Calculus BC | Khan Academy
0:09:44
If x=a(cos2θ+2θsin2θ) , y=a(sin2θ-2θcos2θ), find d2y/dx2 at θ= pi/8
0:06:01
Find the second derivative implicitly with respect to x for x^4 + y^4 = 16
0:08:37
Parametric vs. Cartesian (vid#4): Second derivative d^2y/dx^2
0:02:01
Differentiate parametric equation, find d2y/dx2, x = a (cos t + t sin t), y = a ( sin t - t cos t)
0:06:19
Given that y=e^xsinx, show that d²x/dx² - 2dy/dx - 2y = 0 (Derivative)
0:03:28
If y=cos⁻⁻¹x, find d²y/dx² in terms of y alone ,second order Ncert continuity and Differentiation...
0:04:01
If `x=at^2`,`y=at`,then `(d^2y)/(dx^2)=`
0:03:02
Find first and second derivative in terms of t, x = 4 sin t, y = 2 cos t. Parametric equations
0:04:49
Class 12- HOD-If x=cost + log tan t/2, y=sin t, find d2y/dx2 at t=pi/4
0:05:15
If x= a secθ and y= b tanθ then find d^2y/dx^2 at θ=π/6 | Class 12
0:02:17
If `x=at^2, y=2at` then `(d^2y)/dx^2` is equal to
0:12:19
Implicit Differentiation (Second Derivative)
0:04:53
12 x If y = cos-1 x, find d2y/dx2 in terms of y alone.
Комментарии