If x=a(cos2θ+2θsin2θ) , y=a(sin2θ-2θcos2θ), find d2y/dx2 at θ= pi/8

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If x=a(cos2θ+2θsin2θ) , y=a(sin2θ-2θcos2θ), find d2y/dx2 at θ= pi/8
  1. GURUDEV CLASSES
  2. If x=a(cos2θ 2θsin2θ)
  3. y=a(sin2θ-2θcos2θ)
  4. find d2y/dx2 at θ= pi/8
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