Relative Velocity Part 2 Kinematics Physics Lesson Tutorial

[sizwea.mabaso]

I learned more on your 5 minute video than I do a 90 minute class

[Beatle]

This video is GOLD! I honestly spent an hour staring and trying to find out where all the sines and cosines were coming from. >.> THANK YOU! <3

[PhysicsEH]

@AncientGearBeast I should have made it more clear in the video that in this example Vr is not the hypotenuse. Pythagorean theorem has the hyp^2 = side^2 + other side^2. In this case one side is Vr, one side is Vw and the hypotenuse is Vs so the formual ends up being Vs^2 = Vr^2 + Vw^2. I hope this helps.

[PhysicsEH]

@YellowBananaaaa I just found your question in my spam box. You don't have to use the resultant, what you do is use whatever component is parrallel with the displacement you're given. In swimmer questions you usually know the diplacement across the river so you match the displ. with the velocity component in that direction. In this question the resultant is in line with the displacement given. In that last video the swimmers velocity is in line (parallel) with the displ so I used that.

[aravindlochaner]

The video you made 7years ago helps me now with my enterance preparation

[Summer]

You're amazing!! I attend the 8th best University in the nation. I have 3 professors and 2 TA's teaching my physics course and collectively they can not explain physics like you do. Thank you!!

[Boogey_Man_]

bro, you're such a bro!. this helps so much!

[PhysicsEH]

@ReddAlertt Hi. The more we do this the better we get at having the sound a bit louder. We will keep trying to get it better. I hope you still found it usefull.

[PhysicsEH]

@ello1234567 I'll tell you a little secret. The calculation answers are on the board just out of view of the camera. I can see the solution when I face the chalk board. Don't tell my students, they think I have a special power.

[PhysicsEH]

@siasorat Hi. You can describe the direction using 2 different methods. One is to call it [E 42 N] which means point to the east and then move 42 toward the north. I think this method is the easiest but some teachers use the seocnd method. The second method writes it [42 north of east] which means go 42 degrees toward the north from the east. I find this method of naming more comfusing. I think you use this method and so my answer looks wrong to you. I hope this helps.

[nezezzr]

Thankyou!!  Made me get my physics homework done. :)

[abhishekkumar-ydqq]

Thanx for clear my concept of relative velocity

[AncientGearBeast]

@PhysicsEH
why didn't u do Vr^2= vs^2+Vw^2 square root?

[khilado]

Thank You so much! I have learned a lot :))

[adityadwivedi]

How is the addition of vectors at the end of video, right ??

[lizabethzita]

Im confused! you calculated sin which i always thought is opp/hyp but you dont have opp, you have adj (4 m/s) ?? how can this happen? or what am i missing here?

[siasorat]

isn't that north of east? cause you find the thetha and it should be north of east east of north would be the other way around 90-42?

[eemakagoma]

Thank you so much! This channel is a lifesaver. #newsubscriber

[Nardib]

at 4:45 should it be Vr= 4.47 s or Vr = 4.47 m/s ?

[RG-]

Sir what you are explaining is Resultant velocity and NOT Relative velocity. The title of these videos is Relative velocity, which is not the same as Resultant velocity.