Abstract Algebra II: introduction to modules, 3-1-17

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We're in Dummit and Foote's 3rd edition, Part III
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SO GLAD you have videos about modules!!

ClumpypooCP
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(21:07) Can you help me understand why we need the annihilator condition am=0 in order to make M into an (R/I)-module. Checking the axioms using the action (r+I)m=rm on R/I x M --> M, I did not seem to need the condition am=0. Hence, I suspect I missed something important. Thanks in advance.

adamrichard
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If 0 is a identity with an addition operation, 0 in R if we operate with an element m of M, is that true that 0r m = 0m?

samsualam
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sir which book you are preferring for module theory?

GopinathShanmugam