(Abstract Algebra 1) Definition of a Group

The definition of a group is given, along with several examples.

[pulkitrustagi]

Can we just take a moment to appreciate the fact that this course is accessible to all, completely free and easy to understand!

[sachinramsuran]

The approach you took at the beginning of the explanation is what made this video different from all others. Sometimes persons start with the abstract and then lead to the examples by which time the viewer is completely confused. However, you took the difference approach and i understood perfectly. Thank you.

[DeepakVerma-ecfg]

The way the topic has been explained, the approach, is great. You made it so easy to understand. Appreciable.

[simoofficial]

Thank you very much for this! I am in my first week of Linear Algebra in college and this was very helpful.

[sartajmuzafer]

Wonderful.... Video helped me a lot in understanding the topic....
Thank you sir... For...providing Sach a easy way to understood these tough topics of math's ....

[jpdemont]

Excellent series. Thank you. And thank you especially for noting that many authors and mathematicians are sloppy with their notion when they fail to include the binary operator in the group name or definition. That confused me for so long.

[chowdhury]

Good 1, keep up the good work, short and succinct, and undoubtedly the best

[nolbycayetano]

Great video. Very helpful in helping me cement the definition of a group. Thank you!

[dm]

very helpful keep up the good work...!!

[viktable]

@learnifyable I think lack of a/0 doesn't disuqallify that from being a group, there is just an exception.

[dhananjaysahani]

Thank u very much sir.
I understood each nd every concept through ur video

[morganthem]

This is so succinct and easy to learn from

[abdoulayebalde]

Can you make a video on lattice as soon as possible cuz O am having my exams soon and your video is gonna save my life

[rhysmc]

Wow man, you're pretty much just as good as khan academy, damn

[ohemengstephen]

THANK YOU VERY MUCH. But i think <Q, *> IS A GROUP. At times the inverse of an element can be the element itself mostly from the cayley's table
But if am wrong you can help me too

[keerthigag]

Nice. easy to understand, thank you so much

[sihamrasheed]

I have a question on 11:00 you said it's not a group because zero is part of the set but why is the first one considered a group if zero is also part of the set and zero doesn't have an inverse, so doesn't that mean it shoudn't be a group?

[Angel-VTek]

What about:

a, b elements of N.
a*b= a^b

Is that a group????

[Leonardo-oycx]

Does this mean that when we consider a group of the set of rational numbers we consider subsets as well? In the example rational numbers under addition: if we add (1/2 + 1/2) we get an integer. Is it correct to say that the set of integers is a subset of the rational numbers therefore it does not violate closure under addition?

[jessicaibaliguat]

thank you so much.. this is a great help for me.