Rotational Kinetic Energy | Rolling Without Slipping (AP Physics 1)

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Being able to use the law of conservation for energy makes physics problems a lot easier. One way that we say that energy is conserved in rotational motion is by saying the object is "rolling without slipping". This is the same as when we said "a frictionless surface" in linear kinematics.

For rotation we need friction to make the object rotate but when the object doesn't slip in relation to the surface then there is no work done by the friction force and energy is therefor conserved.

We will look at 2 examples in this video as well



If there is a topic you want me to do leave them in the comments below.
#physicstutor #rollingwithoutslipping #conservationofenergy
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**PLEASE NOTE** At 12:30 I forgot to square the Vt. I did remember to square the R which is why I could cancel them out. The numerical answer is correct because I did the work before had. -1 for me!** (This edit was picked up by a viewer and I thank you for letting me know!)

themathandphysicstutor
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Im self studying and these videos give me so much confidence that I am learning thank you

riotbalanceteam
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wow great video, just watched all energy videos and im rdy

samyang
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Thank you so much for this amazing explanation!

shiny-
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thank you so much for amazing video... but i have a question... for the second problem isn't like the initial high height of the ball on the incline h = radius + height of the incline initially?

totmanthescorpion
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With the forces on the ball, what about Fg Parallel? That's the main force making it roll in the first place, right?

crazyJC
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is there a likelihood of "rolling with slipping" on this year's exam?

arnavmangal
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So essentially, rolling without slipping makes it so that the total energy of the final will be the sum of the tangential kinetic energy and the rotational energy? I am a bit confused about when I should be equating the gravitation potential energy or any other potential energy to both the tangential and rotational kinetic energy.

shartkins
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This explanation of why the static friction force does no work is popular on the internet, but I'm just not buying it. The point of contact is the base of the wheel, but the bonds in the wheel transmit the force to the rest of the wheel. Translationally, we apply Newton's 2nd law to the center of mass. The static friction force opposes the motion of the center of mass and therefore does negative translational work on the wheel. The static friction force also produces a torque that does positive rotational work. Presumably these two cancel out (didn't work it out yet) so the net work is 0. In your example, the ball needs some force to the right.

БрайанСеммс
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since the normal force is not coming from the center as you said, does the normal produce a torque? Ugh, this sounds like a dumb question for some reason!!

maanasachandra