Rolling without slipping problems | Physics | Khan Academy

In this video David explains how to solve problems where an object rolls without slipping.

Physics on Khan Academy: Physics is the study of the basic principles that govern the physical world around us. We'll start by looking at motion itself. Then, we'll learn about forces, momentum, energy, and other concepts in lots of different physical situations. To get the most out of physics, you'll need a solid understanding of algebra and a basic understanding of trigonometry.

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[djcrazybeast]

This is the complete opposite of what I was trying to do I meant “how to roll weed without slipping fingers” but I found this educational video :( I feel like a drop out lol

[pinruihuang]

Thanks Khan Academy, I would probably have failed some classes without you guys.
This is why I decided to donate and everyone should.

[taaaaaaay]

Came back here after 3 years of college. Life is good guys! Push hard!

[aeon]

Been 7 yrs....still pure gold❤❤..Thanks Sir

[rownitasheikh]

david sir;your teaching method is really unprecedented!

[yehuawang]

Another episode of life saver 1 wk before test. When ever I thought i am into college and won't have any help from Khan Academy again, they can always surprise me with the collection of topics taught...thank you!

[karankakkar]

Imagine playing with a 5kg, 4m wide yo-yo

[YitzharVered]

Super duper useful, thank you very very much!

[LyricsCubeDude]

Why do i still bother coming to Physics class when i have this videos teaching me the same stuff but do it better

[neerajparchand]

Please can I know what software you use to explain things in such a creative and perfect way??
A very nice explanation David Sir!!

[soccerboy]

I just had a quiz on this and I didn’t know how to put the rotational KE and linear KE together until I saw this, post quiz 😔. Thanks man! So I has different values for the shapes given, in this case I=1/2mr^2.

[bostangpalaguna]

so beautiful... 2 different scenarios, 1 totally the same calculation

[nevin]

Shouldn't we have taken g as g sin theta in the last example, as part of the gravitational force woulf have been cancelled by the normal force..?

[adrianho]

Then Net external force on the yoyo is not equal to mg? Because F = ma_c.m., while the centre of mass is not accelerating at g ms^-2. If it is accelerating at g, then v_c.m. = (2gh)^0.5

[anusheelsolanki]

5:06 The center of mass was not rotating around the centre of mass, cause it's the center of mass.

[andrewgalbraith]

In the first example, wouldn't the CM of the yoyo still be 2 m high when the yoyo hits the ground?
Edit: What I meant was that the initial equation should be mg(h + r) = 0.5mv^2 + 0.5Iw^2 + mgr, but that's equal to mgh = 0.5mv^2 + 0.5Iw^2 anyway. I was confused about whether h was measured to the yoyo's edge or center.

[형경이-sj]

I have a question. In the last two questions, wouldn't the first one rotate quickly under gravity, but the second one rotate obliquely and slowly down?
And when rolling without slipping, the part that touches the ground has zero speed, and the top layer has the fastest speed, but when you rotate at the same distance from the axis of rotation, isn't the speed the same?

[bhinwaramjat]

Sir, kindly answer my question, why didn't we use g'=gsin(thita)

[VineetKrGupta]

Thats some nice stuff !!! Thank you sir it was very helpfull

[NiratPatel]

In the first problem you must use h=6m as the centre of mass is 6m from the ground