If functions f: A→B and g: B→A satisfy g ∘ f=I_A, then show that f is oneone and g is onto. Hene...

If functions f: A→B and g: B→A satisfy g ∘ f=I_A, then show that f is oneone and g is onto.

Hene we have f: A → B & g: B ⟶ A satisfy
gof =I A
g=f^-1
⇒f^-1=g_is the inverse of f.

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