In the figure, the capacitances are C1 = 1.0 µF and C2 = 3.0 µF, and both capacitors are charged to

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In the figure, the capacitances are C1 = 1.0 µF and C2 = 3.0 µF, and both capacitors are charged to a potential difference of V = 100 V but with opposite polarity as shown. Switches S_1 and S_2 are now closed. (a) What is now the potential difference between points a and b? What now is the charge on capacitor (b) 1 and (c) 2?

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Just awesome, thank you so much man!!!

RHYS.TV

why q sub 2 -q sub 1 and not the other way around

subscribes

Thanks for your I have a small doubt that why do the total charge of both systems had a same value, and why it didn't

osalthuduwage

@ 3:00 in:

Why q2-q1 and not q1-q2? Isn't q2 negative?

patricklambdin

on mark 39 second, how can you tell they are parallel? it looks like a series circuit to me?

ajnewyork

on mark 39 second, how can you tell they are parallel? it looks like a series circuit to me?

kevinchang

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