Code Challenge - Python 001 Beginners - Return half of a given string

Welcome to the first code challenge, Python challenge 001. In this Python code challenge series we hope to compliment the existing Python courses on this channel. Code challenges are for people looking to sharpen their Python skills first at a beginner's level with the ambition to then move into more advanced challenges as we progress.

✨Challenge:
Given a string of any length, return 50% or half of the given string.

Notes/Constraints:
Should a given string have an odd number of letters, round down to the nearest number.

00:00 Introduction
02:06 Solution

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[KarminsLynn]

string = input("Enter a string: ")

needed = len(string)//2

for i in range(needed):
print(string[i])

[ApexDefenceContracting]

for 001 this is the code i got.
solution = input("Number: ")
answer = float(solution) * float(.50)
print(answer)

[rishabhsharma]

can't we do this str[:int(len(str)/2)]

[kingofartsofficial]

I am not bragging as a beginner I wrote more user friendly programe by taking input and then giving half len of input .
isn't it good?

[RetroX]

Awesome tutorial! One question, what if I want the odd character to be in the first half of the slice instead of the second half? How would I achieve that?

[chaotic_academia]

There's a formula .rsplit(' ', 1)[0] for a str with spaces