Viewer's Request: Algebra #2: Mixture Problem

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We will solve:
If a 30% solution is mixed with a 60% solution and 10kg of 0% solution, you obtain a 36%. But if they are mixed with 10kg of 50% solution you obtain a 41% solution. How much of each solution are you mixing?

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[tsoojbaterdene]

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[gokulgocool]

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[hajiratanvirhajiratanvir]

Great explanation especially making diagrams for understanding and differentiating between equations, that was awesome and easy to get it. Thanks stay safe and blessed . Have a nice weekend 🌹✌️🤝

[sandipanmondal]

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[dovasd]

I love your videos, and I’m a big fun of your channel. Will be possible to explain in a follow up video why the 10 kg of the 0% solution (practically this is 10 kg of the actual substance, not disolved) is eliminated (multiplied by zero) and not added

[jaymahaffey]

I love your videos but I think this one has a finer scientific issue to be addressed. These should either be described as dry mixtures rather than solutions or solutions given some allowance for concentration/loading. Using the weight of a solution alone assumes they are all the same concentration and they may not be. As a matter of fact they will not be if the final concentrations are different. Don't take that as criticism, it's an excellent solution to a problem many people don't even know they will ever need to solve, and most won't. I just happen to do it occasionally using both solids and liquids and without great care, confusing concentration, weight per gallon and bulk density can lead to miscalculation..