Geometric Derivation of Centripetal Acceleration | Doc Physics

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Maybe your teacher told you that a = v^2/r. Should you believe him?
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Thanks & a good job, keep posting such kind of informative videos!

MonibRashid
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Why is the angle between the tangents and lines parallel to the x axis theta?

LloydXL
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I've been looking for a good derivation, this one seems to fit the bill. Thanks.

I'll have to watch it again though, as I'm not familiar with those unit vectors signs "j hat" and "i hat". Another thing was completely removing the (-v^2 / r) from the limit. is it because the limit is in terms of theta and so we treat (-v^2 / r) as a constant? Kinda like how we take constants out of derivatives and integrals?

phynos
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so many show how theta is = in uniform circular motion but I have seen No one prove it what is the geometrical principle
that explains it? again it looks like you have said theta is = without a proof theta is the key the rest just follows you are
no alone many who "prove" uniform circular motion do not deal with theta ? why

williampeters
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Sir how you use (d) equal to 2theta radius

inamullah
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Wouldn't (or couldn't) you just use L'Hopital's rule to take Theta to limit with sin(theta)/theta? Seems easier than Taylor series way.

Titurel
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OMG such an unnecessarily complex presentation. Guaranteed to cause a headache.

qualquan