An Interesting Infinite Sum of Products

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The Taylor series for Arctan(1) is 1 - 1/3 + 1/5 - 1/7 +..., which equals pi/4, so half of this series is pi/8.

Blaqjaqshellaq
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This is a rephrasing of the Madhava–Leibniz [and Gregory?] series. Expanding partial fractions and writing out the sum in full gives the familiar series.

itsphoenixingtime
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Wolfram alpha can do it you just need to specify the problem better, if you input:
sum_{n=0}^{inf} 1/((4n + 1)(4n+3))
It gives you pi/8

VincentKok
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You can also say: S = (1/2) * arctan 1 = (1/2) * pi/4

inigom
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Appliquer la formule: 1/(a×b)=1/(a-b)×(1/b-1/a)

sadekmebarka
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