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z^4+4z^2+16=0
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Solve the complex roots for z^4+4z^2+16=0 complex numbers.
Another way of applying the nth root formula.
The nth root of a complex number:
[r(cosθ+i sinθ)]^(1/n)=r^(1/n) (cos(θ+2kπ)/n+i sin(θ+2kπ)/n), where k=0,1,2,…,n-1.
Solve for z^4+4z^2+16=0.
The nth root of z^4+4z^2+16=0.
Find the nth root of z^4+4z^2+16=0.
Welcome to join and feel free to raise/ask questions (if any) 🤗
#complexnumbers
Another way of applying the nth root formula.
The nth root of a complex number:
[r(cosθ+i sinθ)]^(1/n)=r^(1/n) (cos(θ+2kπ)/n+i sin(θ+2kπ)/n), where k=0,1,2,…,n-1.
Solve for z^4+4z^2+16=0.
The nth root of z^4+4z^2+16=0.
Find the nth root of z^4+4z^2+16=0.
Welcome to join and feel free to raise/ask questions (if any) 🤗
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