Python Problem 3: Solution | Python Tutorials For Absolute Beginners In Hindi #108

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[RohanSharma-qrfy]

Realising actual learning comes when we ACTUALLY practice programs

[vasim_delhi]

lst=[]
num= int (input("How many variables you wants to input : "))
for i in range(num):
lst.append(input("Enter ELement : "))
print(f"The ordered list is : {lst}")

rlst= list(reversed(lst))

print(f"The reversed ordered of list using Reveresed function is : {rlst}")
rclst = lst[:]
rclst = lst[::-1]

print(f"The reversed ordered of list using slicing method is : {rclst}")

clst = lst[:]
n= len(clst)
m=int(n/2)
for i in range(0, m):
if (i==n|i>n):
break
else:
item=clst[i]
clst[i]=clst[n-1-i]
clst[n-1-i]= item
i=i+1

print(f"The reversed ordered of list using swap is : {clst}")

if (rlst == rclst==clst):
print("All the methods are giving the same result!!")

[kohinoorteamyogeshchhabra]

Yes bhai phle to muje smj ni aya tha phr maine dubara dkhi video ab mera dout clear ho gya tq Harry bhai

[UrduSada]

Sir me Starting se Dekh raha hu Abhi Chapter 31 me hu. bohot hi kamal ke tutorials Hain.

[rafsanhasan]

a = sorted(list(map(int, input().split())))
print(a[::-1])
print(list(reversed(a)))
for i in range(len(a)//2):
a[i], a[-(i+1)] = a[-(i+1)], a[i]
print(a)

[shivanshaghor]

# Easiest way
lst =[1, 2, 3, 4, 5]

list1 = lst[:]
list1.reverse()
print("Original list - ", lst)
print("First reverse list - ", list1)


lst2 = lst[::-1]
print("Second reverse list - ", lst2)

last = len(lst)
for i in range(last//2):
temp = lst[i]
print("Temp", temp)
print("Last", lst[last-1])

lst[i] = lst[last-1]
lst[last - 1] = temp
last=last-1
print(lst)

if lst == list1 and list1 == lst2:
print("All are working properly")

[mohammadsaqib]

Harry bhai aapto iitian nkle aur channel pr iit ka tag v nhii waah🔥🔥🔥❤️❤️

[kamigcuf]

print("Enter the elements of list one by one ")
length=int(input("enter length of list"))
My_list=[]
for i in range(length):
list element")))
print(My_list)
print(len(My_list))
reverse1=My_list[:]
reverse1.reverse()
print("My first reverse list is:", reverse1)
reverse2=My_list[::-1]
print("my second reverse list is", reverse2)
reverse3=My_list[:]
for x in range(len(reverse3)//2):
reverse3[x], reverse3[len(reverse3)-i -1]=reverse3[len(reverse3) -i -1], reverse3[x]
print("My third reverse list is:", reverse3)
if reverse1==reverse2 and reverse2==reverse3:
print("all lists are reversed successfully")
else:
print("all lists are not reversed successfully")

[ajaymehta]

size=int(input("no of element in your list"))
lisr=[]
for i in range(size):
lisr.append(int(input("enter you first element")))
print("your list is READY", lisr)

reverse1=lisr[:]
reverse1.reverse()
print(f"This is the first reverse

reverse2=lisr[::-1]
print(f"This is the second technique to reverse this{lisr}is{reverse2}")

reverse3=lisr[:]
for i in range(size):
reverse3[i]=size-i
print(f"this is third technique reverse this{lisr} is {reverse3}")
if
print("yes these list are all matchable")

[WHxRaghuvansh]

def reversinBy3(*args):
yourlist = []
for i in args:
yourlist.append(i)
print(f"Method 1- {yourlist[::-1]}")
yourlist.reverse()
print(f"Method 2- {yourlist}")
for index, i in
yourlist[index] = yourlist[i]
print(f"Method 3- {yourlist}")


reversinBy3(2, 4, 65, 453, 23, 34, 56)

[desichokre]

# Foods and Calories
ls = []
while(True):
print("Please add a number to your list")
l = int(input())
ls.append(l)
print("Press 'y' to add another number to list or 'n' to exit")
a = input()
if a == 'y':
continue
elif a == 'n':
break
else:
print("Invalid Input")
exit()

print(f"This is your current list {ls}")
print("Reversed list from Python-Inbuilt method =", end=" ")
ls.reverse()
print(ls)
ls.reverse() # Used here to get the origin list back
print("Reversed list from String-Slicing method =", end=" ")
print(ls[::-1])

lg = len(ls) # lg = Length of the list
for i in range(0, lg//2):
ls[i], ls[lg-i-1] = ls[lg-i-1], ls[i]
print("Reversed list from Special method =", end=" ")
print(ls)

[Swarnimshow]

#number 1

n = int(input("How many items is in your list\n"))
list1 = []
print("All the three reverses will give the same output\n")
for i in range(n):
s = int(input(f"Enter your elment no. {i+1} here:"))
# append function add the element of the list
list1.append(s)
reverse1= list1[:]
reverse1.reverse()
print(f"First reverse of {list1} will be {reverse1}")
# method 2
reverse2 = list1[:]
print(f"Second reverse of {list1} will be {reverse2[::-1]}")
#method 3
reverse3 = list1[:]
for i in range(len(reverse3)//2):
reverse3[i], reverse3[len(reverse3)-i-1] = reverse3[len(reverse3)-i-1], reverse3[i],
print(f"Third reverse of {list1} will be {reverse3}")

[nayan]

challenge accepted

# given_list = list(map(int, input("Enter").split()))
given_list= [3, 4, 5, 6]
choose_method= int(input("Enter method number which you will use "))
if choose_method == 1:
given_list.reverse()
print(given_list)
elif choose_method==2:
print(given_list[::-1])
else:

n=len(given_list)
for i in range(0, n//2):
temp = given_list[i]

given_list[n-i-1]=temp
print(given_list)

[gameyguys]

lis1 = list(input("Enter the numbers you want in list : \n").split(', '))
lis2 = lis1[:]

# First Method

lis2.reverse()
print(lis2)

# Second Method

lis3 = lis1[:]
lis3 = lis3[::-1]
print(lis3)

# Third method

lis4 = lis1[:]
for i in range(len(lis4) // 2):
lis4[i], lis4[len(lis4) - i - 1] = lis4[len(lis4) - i - 1], lis4[-i]
print(lis4)

# Here the Logic is that [-i] means that the (len which means the amount of arguments in variable) decrease with [
# -i] and [-1] for some reason reverse the list without slicing maybe we can find it in the previous videos but for
# now it is enough

[samyakjain]

11:17 aapne school me seekhli thi coading

[smumarhashmi]

# Python practice problem 3 solution

# Take the size of the list from the user
print("Enter the numbers of the list one by one")
size = int(input("Enter size of list\n"))

# Initialize a blank list
mylist = []

# Take the input from the user one by one
for i in range(size):
list element\n")))


#First Method Used to reverse mylist
reverse = mylist[:]
first_method = reverse.reverse()
print(f"First method to reverse {mylist} is {reverse}")

#Second Method used to reverse mylist
reverse1 = mylist[:]
second_method = reverse1.reverse()
print(f"Second method to reverse {mylist} is {reverse1}")

#Third Method used to reverse mylist
reverse3 = mylist[:]
for i in range(len(reverse3)//2):
reverse3[i], reverse3[len(reverse3)-i-1]= reverse3[len(reverse3)-i-1], reverse3[i]
print(f"Third method to reverse {mylist} is {reverse1}")
if reverse == reverse1 and reverse1 == reverse3:
print("All the methods give same results")

[sanatanivibes]

# practise problem 3
# food and calories
print("Enter the list")
lst = input()
lst1 = lst.split(", ")
length = (len(lst1))
lst2 = list(lst1)
new = []
var1 = length


def method1():
var4 = reversed(lst2)
var5 = list(var4)
print(f"List reversed by builtin method: {var5}")


def method2():
var = lst1[::-1]
print(f"List reversed by slicing method: {var}")


def method3():
for i in range(1, length+1):
var2 = var1 - i
new.append(lst2[var2])


method1()
method2()
method3()

print(f"List reversed by swapping method: {new}")

[avipranami]

#mySolution

lst = [int(input("Enter the list Element:\n")) for i in range(3)]
print(f"Your list is {lst}")
while True:
choice1 = int(input("Enter 1(Traditional Method), 2(Slicing Method) or 3(Swaping Method) for reverse the List:\n"))
if choice1 == 1:
lst1 = lst[:]
lst1.reverse()
print("The Answer of First Method is :", lst1)
elif choice1 == 2:
lst2 = lst[::-1]
print("The Answer of Second Method is :", lst2)
elif choice1 == 3:
for i in range(len(lst)//2):
lst[i], lst[len(lst)-i-1] = lst[len(lst)-i-1], lst[i]
print("The Answer of Third Method is :", lst)
choice2 = input("C for Continue and Q for Quit:\n")
if choice2.capitalize() == 'Q':
break
if choice2.capitalize() == 'C':
continue
print("Thank You.")

[travelpanchi]

swapping- list2=list1[0:n]
list2=list1[n:0]
print[list1]
I applied the above method for swapping and got the reverse list, is it correct ? altho it worked and is pretty simple as compared to the solution given in the video

[rachitsaxena]

n=input("Enter the numbers you want to add in the list\nREMEMBER--Spacing is consider as the end of one term\n")
lst=n.split(" ")
print("THIS IS THE ORIGINAL STRING\n", lst)

list1=lst[::-1]
print("\nreversed list from slicing method\n", list1)

list2=lst[:]
list2.reverse()
print("\nreversed list from inbuild method\n", list2)

list3=lst[:]
lambai=len(list3)
temp=list3[0]
list3[0]=list3[lambai-1]
list3[lambai-1]=temp
print("\nreversed list from swaping method\n", list3)

if list1==list2 and list2==list3:
print("\n\nlist are similarly generated from all the methods")
else:
print("\n\nlist generated by all the methods are different from each other")