Functional Analysis 18 | Compact Operators

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This is my video series about Functional Analysis where we start with metric spaces, talk about operators and spectral theory, and end with the famous Spectral Theorem. I hope that it will help everyone who wants to learn about it.

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00:00 Introduction
02:39 Definition
03:13 Example

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I hope that this helps students, pupils and others. Have fun!

(This explanation fits to lectures for students in their first and second year of study: Mathematics for physicists, Mathematics for the natural science, Mathematics for engineers and so on)
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9:02 By the way, it is not necessary for A to be bounded: it is suffisent to show A is point-wise bounded to apply Ascoli Theorem.

i.e. {g(x)/g in A} bounded for each x in [0, 1]

Jooolse
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10 minutes with you >> 1 week in class

zachchairez
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great video! the series is amazing 😊
at 9:20 I dont understand why bounded and equicontinuity holds for the closure as well?

jonasw
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What software do you use to write the math? Also love your videos thanks for these!

kellyramsay
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This might come in a later video, but what can we say about compact operators? Why would it be nice to know that an operator is compact?

aleksherstyuk
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As usual, great ! Will there be anything about Hilbert-Schmidt operators ?

trondsaue
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I'm couldn't really understand what happened at 3:53 for a particular f in C[0, 1], how and why are you defining Tf at s with another function k? What is the purpose of this k, and how did it come, in the first place?

AadityaVicramSaraf
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can I ask for verification. if the operator is bounded, we can also say that image of B_1(0) of T also bounded?

ferry
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How to show that the closure of an equicontinuous set of functions is equicontinuous though ?

StratosFair
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8:40 uniformly -> uniformely -> uniformly 👀

Jooolse