Hard Math Problem With Exponents @olympiadlearning #maths

Hard Math Problem With Exponents
@olympiadlearning #maths #mathstricks #exponents #olympiad

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Here, I have solved this Hard math Problem in the following way , please have a look.

2^ 22 x 3^ 33

= 2^(2x11) x 3^( 3x11)

= (2^2)^11 x ( 3^3)^11

= 4^11 x 27^11. ;

This above step is taken by the following formulae,

a^m x b^ m = ( a b ) ^m

Here, exponents are same.

The next will be,

= ( 4 x 27 ) ^ 11 ;

The final outcome is ,

108^ 11 .

Thank you so much for reading .

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