Converting to vertex form and identifying the vertex

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👉 Learn how to identify the vertex of a parabola by completing the square. A parabola is the shape of the graph of a quadratic equation. A quadratic equation can be written in the standard form (i.e. in the form y = ax^2 + bx + c) or it can be written in the vertex form (i.e. in the form y = a(x - h)^2 + k, where (h, k) is the vertex.)

Given a quadratic equation in standard form, to obtain the vertex of the equation, we use the process of completing the square to rewrite the equation in the vertex form and hence extract the vertex of the parabola formed by the equation.

Organized Videos:
✅Completing the Square
✅Find the Value C that Completes the Square
✅Standard to Vertex Form by Completing the Square
✅Find the Vertex by Completing the Square

Connect with me:

#Completingthesqaure #quadratics #brianmclogan
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sir can i just say you are the only reason im actually passing and learning math right now

marissasat
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I have a test next week. Thanks so much for helping me study.

kristinhelms
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Hi Mr. Logan! I am a 7th grade Math teacher, teaching Math 2 (sophomore level) and we are currently in our Quadratics unit. This video was super helpful in explaining how to go from quadratic form to vertex with a leading coefficient that isn't 1. One question, how did you explain to your students the reasoning for subtracting the constant term (found by completing the square) multiplied by the leading coefficient? Thanks in advance!

veronicawalker
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This was soooo helpful my teacher is Bosnian and I am American so the language barrier makes it hard to understand what he is explaining and how he explains things and this really cleared everything up and helped me with my homework... this was great thank you so much

jessicaschiel
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This video really helped, since my math class is on a quadratics unit. I have one question though...How do you go from standard form to vertex form, if the values are in decimals? Is it the same process?

nathanows
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Wishing you a good day from Western Michigan University

shofialom
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this is tough to write in a paragraph. The best I can do is take the quadratic equation of the path of your projectile it should be in ax^2+bx+c form and then find the vertex which will be ((-b/2a), f(-b/2a)) The y value of the vertex will be your maximum height

brianmclogan
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Wow!!! your videos are really helpful, thanks!!

sherice
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I would like to know how to determine the vertex, when asked as what is the maximum height of an object reaching once launched, kicked, thrown, etc. off of an elevated surface... for instance, may you provide a problem or demonstration please! thanks in advance!

lICKENDsPLIT
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Hello, May I ask..How to do 2x^2+12x+13?

damntwice
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1:48 im not sure if i have to do the same if my a isnt 2 it is 1/2 ( my problem is y=1/2x²-6x-10)

swaggyperosn
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bro i don’t understand this i’m gonna fail guys🙃

olive.
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hey guys, I have a test tomorrow and still don't get this. Mine is a=2, b=13, c=15. But I'm confused because I can't do the same thing because he divided by 2 and got a whole number I would get a fraction.

guiskrr
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It would have been much faster and simpler if you just factored the 2 out of 18

thename
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hello I have a question I am trying to find the vertex of y=3x^2+12x+4 I cannot find the vertex using the -b/2a form it gives me a high number please help

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