[March SAT Math] 10 Must Know SAT MATH Questions (2025)

In this video, I break down 10 essential SAT Math questions that you absolutely need to know before the March SAT 2025! Whether you’re aiming for a perfect score or just trying to boost your score, these questions will help you master key concepts and strategies that appear frequently on the SAT.

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00:00 Intro
00:11 Question 1
01:37 Question 2
02:26 Question 3
03:16 Question 4
04:35 Question 5
06:14 Question 6
07:10 Question 7
08:56 Question 8
09:50 Question 9
10:59 Question 10
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[Hara_Mine]

You can use desmos for a lot of these problems:
1) Plug x(kx-56) and y=-16 add a slider for k and slide it until it doesn't touch the y=-16 line anymore.
2) plug both equations in and then replace h with the answer choices until you find the answer.
3) plug in the equation and make a and b a random number (cause they are constants it doesn't matter what you plug in). Then multiply the products after divide by the sum of a and b. you will get 0.01754 as the answer which is 1/57 in decimal form.
4) The method shown in the video is the fastest way to solve this question
5) create a table with the points (1, 9) and (2, 219). Then plug in the regression equation (y_1 ~ a^(x_1) -b) which will give you 6
6) Plug and dash
7) plug in point (1, 1) as (h, k) (again constant so doesn't matter which numbers you use) then plug in the point A accordingly to the center. find the distance between the center and point using distance (points) in desoms then use the pythagorean theorm to find distance between A and B (sqrt( distance^2 +distance^2)) it will give you ~14 which is sqrt(206)
8) Plug in the given points in the graph into a table and build a regression equation (y_1~ 2x_1^2 +bx_1+c) which will give you the points for c and b and then multiply them together to get the answer.
9) Plug in both equations in desmos. Replace p with answer choices and select the answer which is closest to the lines overlapping.
10) Avoid using desmos for this: it is not possible to get the precise value not worth it to spend time on this with desmos.

If you learn how to use desmos properly you will easily get 700+ on the SAT to get 750+ learn the stats and geometry formulas and concepts. to get 800+ do the most obscurely hard problems ever given on the SAT. For math section go back to the old paper and pen test and do them (skip complex number problems). You got this!!

[morna]

Thank you, this has literally saved me with 24 hours to test day

[OverclockingCowboy]

For Question 4,
b = 0.89c
b+c = 1.89c
a = 24.03(b+c)
a = 24.03(1.89c)
a = 45.4167c
a = 45.4167(b/0.89)
a = 51.03b
Thus,
a is 5103% of b

[soldierregi]

dude spammed the link on reddit, but the video is actually good ngl

[aryashah]

for number 23 at 10:53, you can graph the two equations into desmos and make x any value you want for both equations. then you can make p a slider for both and test out all the answer choices. the correct answer is the one where the two functions fit right on top of each other on the graph. this may be much easier to do.

[hdeed]

for people who have SAT on 5th, almost 90% of what u saw here could be done on desmos, for eg question 5 took me 30 seconds max, take supposed values of c (i took took 4) and then 2c will be 8, add these values to table in desmos and equate table to exponential equation given in the question, it will give you b which is 6, learn to play smart boys, keep ur heads up

[tatvav]

dude this helped me so much, I just took the dsat rn. I was able to finish module two with 2 minutes left, and it was all thanks to this video. You’re a godsend bro 🙏🙏🙏

[ange_does_gacha_art]

Thanks, dude. i was struggling to solve most of these problems in the practice test, and the question bank doesn't do a good job in explaining the answer or their own answer is lengthy . Im not very good with desmos, so this video really helped me. Im writing my first ever SAT on march 8.

[muhammadausaf]

one of the best SAT videos on internet ngl; just straight to the point

[guzy]

this video covered all the topics i was struggling on! i havent been able to find other videos covering all these topics so this is a godsend haha esp bc im taking the oct5 sat tysm so youre the best<3 !!

[RisetotheEquation]

For Question 9 (9:51) you can literally solve in two steps with desmos. Step 1: Create a table and enter two points from the original f(x) equation. Obvious ones that you should be able to do in your head are (0, 1) and (4, 1.84). Step 2: Enter the regression y1 ~ (1 + p/100)^x1. Your answer is given under REGRESSION PARAMETERS. p = 16.4674. So the answer is (A) 16. This took 15 seconds. Not showing kids how to use this amazing tool that the college board actually allows you to use during the test is borderline criminal.

[RisetotheEquation]

You can solve Question 5 (4:35) in less than a minute with Desmos. Enter a table with the two points exactly as given. Next, enter a slider for c and set it equal to 1 (any value will do). Then type the regression y1 ~ a^x1 - b. After that, you just replace b with each answer choice until r^2=1 (that means it's a perfect regression). This will only happen when b=6. You can also tell from the graph that b=6 because it's the only value for which the graph goes through the two points.

[battlecatsplayer]

i took the october sat and this is lowk rlly good; not spot on, but most of the problem he solved were on the sat. I would argue that even though some of his predictions were not relevant to the october sat, it is imperative to know them for practice and future sat

[mandipSapkota]

i wish i had idk option in dsat 4:56 XD . great video btw, you saved my sat tomorrow

[doinker_]

Yo bro this is a really good review these questions are definitely important ones. Good stuff

[zein_co]

Thank you so much @JZ Test Prep

I almost forgot the formula of Vietan.

ax^2+bx+c
And let p and q be the roots.
the Vietan's formula states that
pq = c/a
p+q = -b/a

I hope this helps.

[OverclockingCowboy]

Question 7. DESMOS

Fastest way is to use the distance function and set (h, k) to zero.

A = (1, rad102)
B = (-rad102, 1) or B = (rad102, -1)
AB = distance (A, B)

The difficult part here is figuring out the coordinates of point B. The 2 radii (AC and BC) are perpendicular to each other. We can use the concept of “negative reciprocal” to calculate point B. If A = (a, b), then B = (-b, a) or (b, -a).

As a proof, assume a=5 and b=9.
Equation of line AC is simply y = (9/5)x
Equation of line BC becomes y = -(5/9)x
Point B can be at the fourth quadrant or the second quadrant.
For the point at the fourth quadrant, x=9 and y=-5.
For the point at the second quadrant, x=-9 and y=5.
Lines AC and BC have the same length rad (81+25). Points A and B also lie on the same circle, having the same distance from the center C.

If you have DIFFICULTY figuring out point B, you can measure the radius first.
A = (1, rad102)
C = (0, 0)
r = distance (A, C)

You can create your own coordinates that are perpendicular to each other relative to the center. The XY axis is convenient.

D = (0, r)
E = (r, 0)
DE = distance (D, E)

[headfinisher]

I just gave the exam and u came in clutch for 2 or 3 qstns today

[Andrew-Tsegaye]

subscribed! Bro, you deserve a many likes, subscribers.... Thank you so much!

[jivrajnarula]

Dude these are so good plz post more I’m taking October