Calculus 1: L'Hospital's Rule (12 of 25) Example 11

In this video I will use L'Hospital's Rule to solve limit-as-x-approaches-infinity of {(x^2)[e^(-x^2)]}.

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[nikulp]

e^(infinity)^2 does not equal the same infinity. It equals aleph 1, which is bigger than aleph 0. aleph 0 is the infinity in the original question.