Quantum Spin (2) - Pauli Matrices

[Undergraduate Level] - An introduction to the Pauli spin matrices in quantum mechanics. I discuss the importance of the eigenvectors and eigenvalues of these matrices, as well as the outer product. I also provide an introduction to matrix multiplication. This is the second video in my series on quantum spin.

[pranjalisharma]

i have never laughed while seriously studying something, until now!! thankyou for those tiny "btw don't be afraid" reminders and those cute pauli symbols, thankyou for the whole video.

[sahhaf]

A very important thing about the calculations @19:50 : All these things are written using z-basis. Hence we got sigma_x's representation in z-basis.

[fsloadmaster]

Eigen in German is an adjective which actually means "own": specific of someone or something, as in "in my own opinion", or "in its own right".

[lorendisney]

Clear and logical with a light touch. Excellent.

[puzu]

Well, this is going to be a journey. Thank you for the work.

[djxcove]

oh hell, it's gonna blow up eventually. You have the potential to be the next khan acedamy. keep up, and please, don't stop making these videos.

[copernicus]

At about 6:20, how do we get the sqrt2 ? In other words if we have the up and down alpha and betas for the X direction, how do we know anything about measurements in the Z direction?

[vorsankoy]

It was really helpful video. Enjoy the ur explanation and fun. Thanks aloot😍

[fndTenorio]

When you say the column vector |ψ> = (α β) without saying the basis, is it always implicit a basis z?

[yyc]

I have a question: since the Pauli matrix can be expressed in the form of outer product, I can understand, for example, σy=|↑y><↑y| - |↓y><↓y| works on |↑x> state is clearly zero. However, if I replace the σy and |↑x> by their matrices, namely (0 -i; i 0) multiplies (1/sqr2, 1/sqr2), I get (-i/sqr2, i/sqr2), which is not zero. Where am I wrong? Thank you~

[wen]

Great video, and helpful. thanks a lot

[ko-prometheus]

Привет,
Очень познавательно!!
Не хватает 3D

[michaeltheisen]

I'm lost.

Oh! there's a part 1.... brb

alriiiight im back. K i get it now.

[jacobvandijk]

The math is good, the physics is very poor.