Friction

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Friction force explained in a simple and practical way!

Friction is a force that opposes the relative motion or tendency of such motion of two surfaces in contact. It acts parallel to the surfaces and is caused by the irregularities present on the surfaces in contact.

There are three main types of friction: static friction, sliding (kinetic) friction, and rolling friction.

1. Static Friction is the force that opposes the initiation of motion between two surfaces that are in contact and at rest relative to each other.
Static friction prevents the object from moving even when a force is applied. It adjusts itself to be equal and opposite to the applied force until the force reaches a critical value, known as the limiting friction. Once this critical value is exceeded, the object starts moving.

2. Sliding or Kinetic Friction: Sliding friction, also known as kinetic friction, is the force that opposes the motion of two surfaces sliding past each other. Once an object overcomes static friction and starts moving, sliding friction comes into play. It is generally weaker than static friction and remains relatively constant as long as the surfaces continue to slide past each other.

3. Rolling Friction: Rolling friction is the force that resists the motion of a rolling object, such as a wheel or a ball, on a surface. Rolling friction is generally lower than sliding friction, making it easier for objects to roll than to slide. It occurs because the object deforms slightly at the point of contact with the surface, and this deformation creates resistance.

In summary, static friction prevents the initiation of motion, sliding friction opposes the motion of sliding surfaces, and rolling friction hinders the motion of a rolling object. Understanding these types of friction is crucial in various fields, from physics and engineering to everyday scenarios where friction plays a role in the movement of objects.

At Manocha Academy, learning Science and Math is Easy! The school coursework is explained with simple examples that you experience every day! Yes, Science & Math is all around you! Let's learn every day from everyday life!
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HW : w= mg= N
2×10 = 20 N=> Nf
Coefficient of static friction(mu) =0.4
fs = (mu)s× N
= 0.4 × 20
= 8 N
But, even the 4N is acting on the object but the fsmax will cancel the force because it is Self Adjusting Force and the force is the less than fsmax ... 😊

rithizx
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Thank you sir for clear explanation about friction ❤

niranjanninja
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your the best teacher i have ever listened to
thanks for your helpful teaching

diaago
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For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App

ManochaAcademy
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Your explanation, teaching is awesome sir. Thanks a lot and lot your service sir.

mgopal
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Sir you explains very well with practicles
We are glad to have a 😊 such type of valuable classes by you sir

DurgaprasadBudi-ij
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I think the answer would be 8N because--
M= 2 KG
W= mg
= 2 KG*10 m/s²
= 20N
Coefficient of static friction= 0.4
therefore, 0.4*20N= 8N

MAdciTy-ve
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Hi, am benard from Uganda am happy to join you

benardbanks
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This helped me a lot when I was doing exams, Thanks! ❤❤

ItsJustAurora.
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This is most wonderful experience explanation, so I like it sir

cholamwambula
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Hello sir your explanation is very well
Love from Nepal❣️

kamalrajkhadka
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I am really glad I found ur channel please keep making such videos now got friction into my head and heart
answer to last question 8N.

priyankakotian
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Why we should not used cos theta instead of tan theta to calculate angle of friction. Sir

ಅರ್ಪಿತಾ-ತಷ
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This is really a very helpful video. Concept is Crystal Clear.

rohitshastry
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Really understood clearly the topic also enjoyed too....🤩🤩thanks sir for your support ❤❤❤

ayushmondal
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The way u taught ch friction now i don't have any doubt in this ch u r superb sirr thankyuu so muchh ❤

soyaroy-xu
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Hi I'm Solomon Manyuot Mabor, from south Sudan am so glad for the work you have done ✅✅✅👍👍🎉🎉🎉.

ManyuotMabor
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Thanking you sir for your effective explanation.

navaidsaquibshaikh
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Sir, i am from mars, and your videos are just awesome 🎉❤

sensei
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The frictional force is 8N.
Therefore the applied force, 4N, is not sufficient to move the box.

adebayoadekunle