Differential Equations: Lecture 2.2 Separable Equations (Version 2)

If you find this video helpful please like and share. I hope this helps someone:)

This course uses the book written by Zill, here is my review of the book,

[tvstation]

Big thank you for introducing Tabular Integration to me, can't believe I'd never seen it before! World changing!

[andrewsilva]

I work with students with disabilities at my community college and am totally glad I found your channel. This will be great to supplement their textbook and lectures!

[joelsteele]

Great instructor! Whatever they are paying you, it's not enough. Hard to find this level of explanatory instruction anywhere.

[rockyboy]

You teach it with lots of energy. It feels like I am part of your class. Thank you.

[NoOne-mxnx]

it's been a long time scene I've enjoyed a math class. Thanks.

[paulshin]

Thank you for the Video! I'm learning DE as a pharmacy student, and very helpful in saving money from college by taking extra credit courses.

[stargazerequiem]

I didn't think I already miss Anna's class after watching this 😂

[rayanracki]

Shoutout from Brazil! Your teaching is saving me on my classes, thank you sir!

[adnandarhamed]

Thank you for saving my life professor, your videos is helping me a ton honestly, my D.E professor sucks(doesn't explain shit, he only reads the book :( i have an exam on Thursday and i feel more confident that i'm gonna pass it after watching your

[NattyPi]

The passion is insane haha these lectures are great!

[BONFACEMORIKI]

wow!! I enjoy your lectures prof .thanks for your good work

[EpicMathTime]

Fun fact: in French (and some other languages) the letter w is called "double v" instead of "double u".

[cristofuscolombus]

18:04, there is a quite problem with arbitrary constant. !!!

at the end of the integrated part:

2*ln(1+u)=2*ln(1+w)+C

Now equation it knows:

2*ln(1+u)+C1 = 2*ln(1+w)+C2

Also rewrite as :

2*ln(1+u)+(C1-C2) = 2*ln(1+w)

or,

2*ln(1+u) = 2*ln(1+w)+(C2-C1)

and these two equation can be written as arbitrary constants with (C2-C1) OR (C1-C2)

which do you want to prefer, does it matter?

yes

if arbitrary constants located in side with y's the answer is:

(1+x^(1/2) -C)/C =y

otherwise, I mean constant stay in side with x's answer is:


y=(c(1+x^(1/2))-1)^(2), mean your result.

I don't know I am wrong but I also ı don't know am truly right to write my problematic question if will this question make anyone else a Genius? It's joke but I felt like an inventor for a while as I wrote this





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[georgettebeulah]

This is so real and can relate and understand from it thank you and will try hard to get it all I can stop to imagine. Thank you.😅😆😀💕

[omarellbad]

What does version 2 mean is it the same as version 1 or i have to watch both of them because i will start this course tomorrow and yeah i should know pls

[iremiposiajayi]

Could you have used integration by partial fractions instead for the first problem?

[pagapulaanrohans.]

question, 31:37 since we thought C=2Č and we got C=4 at the very end, then should Č=2 or is C representing any value (cuz it's an arbitrary constant so that's why it's 4?)

[paulshin]

I have a general Question About the DE graphs. I only have taken Cal1, 2. How could one X-value have multiple y-values? I learned that one X-value could only have one corresponding y-value, but I have seen a lot of functions(in DE textbook) that work against this rule. Simple Example Circle one X has 2 Y value. For some other functions, if you draw a vertical line in the graph, one X-value has multiple y-value. How does this works?

[fastmath]

I pronounce it as "tilda". That's how it is usually pronounced in English. It comes from the same word as "title", namely "titulus" in Latin.

[iremiposiajayi]

Just curious: is there a “proof” for the tabular method?