Separable differential equations introduction | First order differential equations | Khan Academy

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Differential Equations on Khan Academy: Differential equations, separable equations, exact equations, integrating factors, homogeneous equations.

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Why does this one guy literally know EVERYTHING

kurkwelch
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fucking support this channel everyone i hope in 2050 this guy will be recognized by MORE people and he makes it into history books and he becomes a fucking legacy.. not only sal.. but the etire khan acad team..

dogeeatsveggies
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I understand you much easier than my Russian native diff eq professor haha!

jackrotter
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Idk why but your voice is incredibly calming and love your explanation on these concepts

whitwat
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He has is own way of making people understand within minutes 🥺 thank you for being the best tutor

MwansaTaizya
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2:34 "Little more space"  lol

thealexgalaxyoriginal
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Hello i'm from Indonesia..
I see this because of the work of the lecturer. but I don't understand because I'm not very good at English. Thankyou❤️

pujawaraa
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How can you multiply by dx? dx isn’t a number, it’s just a notational convenience for small changes (eg over a small amount of time). Can you explain that logic?

gregoryfenn
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In beams problem we can apply this call separable differential equations, and I have come across with hinged beam, where moment is zero at the hinge, and also x=L, so (L, 0) is a coordinate point, initial condition, given information to find a particular solution ( M=Mx) moment function to a higher degree order differential equation which it only takes place within a member and linked with constrain of the structure, the use of principle of superposition will help us to analyse redundant forces by setting derivative forms.I would like to share my experience....any emai?

thestructuralanalysismatri
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Nice job good learning system help all out thank u

ankursingh
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Thank you for your "advice".

LovinaVargasOfItalia
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In the first example, are we going to do integration by parts in -xe^-x^2 dx? I'm kinda confuse. Notice this one please. Thanks!

renatoedaojr.
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Does someone know why y*dy integrated is equal to (1/2)y ^2 ?
Im very confused because usually y integrated should be equal to (1/2) y ^2.
but why is there the same solution with and without dy?

ascaniuspotterhead
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can someone explain the integration part? where does he get the 1/2 to and all the other stuff from?

ryanhugh
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Hi! Do you think you could make a video on Euler's rule for differential equations?  I don't fully understand it.  Thanks!

billybobandboshow
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Thank you very much sir, very clear and helpful, please please I need to know the software that you are working with please.

nesreenacademy
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At 5 min 56 seconds, couldn't you also multiply both sides by 2 to get rid of the 1/2 factor on each side and then plug in your point to solve for C. Your C would multiply by 2, but since it is an unknown constant that should not effect the answer. I did that and ended up with the answer of y= + - (e^(-x^2)+2)^0.5. My answer clearly is not as pretty, but I think it is also a correct answer.

soccerstudut
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i think its general solution, coz particular solution wouldn't have an independent variable that would vary each time it would have been constant!! If i got it wrong plz tell me what's the difference between particular solution and general solution ??

artistiaay
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On the integration part you treated it like (e^-x)^2 and at the end you treated it like e^(-x^2) ... Isn't that a big mistake?

chupapimunanyo
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sir which software are you using for these videos????

xlaiaryan