An Ingenious Trick for Evaluating a Tricky Algebraic Expression a^8+7/a^4 | Math Challenge

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This math Olympiad tutorial video teaches you a cool trick / method for finding the value of the algebraic expression (sum of an octic polynomial and the reciprocal of a quartic polynomial) a^8+7/a^4 given the value of a-1/a using perfect square formula and substitution.

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Mientras mas videos veo, de este canal, mas admiro el talento de su productor

icems.a.
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Wow! Wasn’t expecting the substitution for 7. That was a good move

owlsmath
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Wow, some Grand Master chess algebra there - loved it!

piman
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Today's problem is interesting, because, after getting a^8+7/(a^4), it is transformed to a^8+(a^4+1/(a^4))/(a^4). Thank you for explaining.
If you want to treat other problems, I would like to inform as below:

[information]
I am also creating and uploading mathematics videos like you, so I would like to introduce you.  
In my case, with regard to mathematics, I had a time to study math for about only 1 to 2 years at university.
When I entered university, I passed the faculty (that students can study normal math) of a national university,
but my parents did not admit me to go to the university.
It is a bitter experience. Therefore, after reaching retirement age, I started creating and uploading mathematics videos.
However, I realized that there were some mistakes about using math words when I explain. (>_<)
Some of the corrections were not made in time, so they are uploaded as they are.
(Please accept this situation.)

Nowadays, I am planning as follows:
"I will publish only my own problems at first, and after various mathematics YouTubers introducing the methods in their videos,
I will upload a video of the answers that I have prepared. So, mathematics YouTubers can compete each other for how to solve.”

That's why I wrote this in this comment.
There are 40 questions in total (excluding the Appendix). [ Note: Most of them are integer problems. ]
I prepared English versions and French versions for them. (But I am a Japanese. So Japanese is used in my videos for the oral explanation.)
For these problems, please refer to the following video.
[Video about 40 problems (Daily motion)]
SY_Math-Science_045 ( [Extra edition] The Special Event - 3 Second half) - Videos Dailymotion
[All my past videos (the 44th and 55th of these are related to the math problems)]
[Daily motion] → SY math science videos - Dailymotion

There are many number problems in the range of high school 10th (and 11th) grade and junior high school.
The problems were created based on the concept of "There are more than one solutions!"
Some of them are similar to some university entrance exams, and some of them are mathematical puzzles.
In addition, there are problems that can be solved by "the Try and Error method."
As for some problems, calculations are troublesome, concerning them, using calculator is admitted.
I guess you will be interested in some of them (or just a few?) if you like math.
If you find my problems interesting, please include them on your videos.
Instead, if you treat the problems that I made, please introduce the source of the problem and advertise my videos because I want to spread them.
(I need the propaganda.)

By the way, regarding video creation, it corresponds to question selection/creation, recording, BGM selection/input, and undercard puppet show,
editing (various cuts, text input, etc.), thumbnail creation/implementation, video management, etc. I do everything by myself.
Therefore, it takes more than a week from start creating to uploading per one video.
Therefore, I cannot make and upload my videos about something with related to them soon. (It takes time.)

"I apologize for writing so much information." Thank you very much for reading my comment.
(I look forward to your future success.) (^o^)

[Appendix]
Of the 40 problems (that I mentioned above), I introduce only 7 problems as samples below.
(Calculators are not admitted to use.) [The last one is not an integer problem.]

Q2-(2)
p^4 - 20p^3 + 90p^2 + 20p - 86 = q (p, q: prime number)  
Find (p, q)

Q3-(8)
m^4 + 4m^2 + 8m + 9 = p^2 (m: integer, p: prime number) 
Find (m, p)

Q4-(3)
p^8 - 16q^8 = rst (p, q, r, s, t: prime number)
Find (p, q, r, s, t)

Q4-(5)
2m^3 + 4m^2n + 5m^2 + 4mn + 4n^2 + 2m + 4n = 2024 (m, n: integer)
Find (m, n)

Q4-(10)
a+b+c+d+e = a^3+b^3+c^3+d^3+e^3 = 5 (a, b, c, d, e: integer) (a≧b≧c≧d≧e)
Find more than 6 solutions.    
(If there are 6 or less than 6 solutions, prove it.)

Q5-(4)
2^a + 3^b + 4^c + 6^d = n! (a, b, c, d: integer, n: natural number) 
Find (a, b, c, d, n)

Q6-(2)
If x^12 + x^10 + 2x^8 + 2x^6 + x^4 - 8x^2 - 9 = 0,
what's x^10 + 2x^6 - 4x^5 + x^2 - 4x -77 ?
(x: complex number)

sy