A-Level Maths: S1-25 Non-Parallel Forces: An Introduction to Ladders

preview_player
Показать описание


Рекомендации по теме
Комментарии
Автор

You're an absolute legend mate. Honestly.

raeedi
Автор

usual excellent tutorial . Well done Jack.

johncameron
Автор

The video content is so excellent, congratulations

ПавелПрохоров-уб
Автор

Great video as always! Could you please explain as to why we cant use F=Mu x R. Didn't quite understand what 'limiting equilibrium' means. Thanks

syedali
Автор

Sir I have a question.Here the value of friction is 28.9 N and the normal force at bottom is 100 N. So the resultant of this two force is 104.09 N something . But this force is acting 73.8 degree with vertical between friction and normal.That means the ladder does not apply force along it's incline.if it gives force along it's incline then the friction and normal are different in this case.
Sir please solve my doubt...Love from India.

ranitbanerjee
Автор

What if the top of the ladder overhangs over the vertical surface it’s leaning against? Would the normal reaction at that top point be perpendicular to the ladder instead of the wall?

kashoot
Автор

Do we need to know about ladders for the aqa spec? Can't seem to find it in my textbook.

kammy
Автор

These questions stink so this video was a big help. you're the man jack 👍

samellis
Автор

when do we know if reaction force is angled compared to when it is perpendicular???

chewypiano
Автор

Thank you very much 🌹🌷
You solved a very big problem for me 💙❤

m.m
Автор

Did you remove the ladders section on your website? Why?

johnlynch
Автор

Does ocr need to know how to do hinges problems?

alanmohan
Автор

Hi, I've just seen a past paper question where the ladder is resting on a smooth vertical wall, and the reaction force between the wall and the ladder seems to be perpendicular to the ladder (jn the mark scheme) rather than horizontal, as I would usually draw it. Could you explain why this may be? Thank you

akipampaloni