Geometric Algebra vs. Clifford Algebra

preview_player
Показать описание
In this short, I talk about the differences, if any, between geometric algebra and Clifford algebra. While some consider them distinct mathematical objects, I consider them to be identical. However, in practice, the way people use these two objects is quite distinct, and you can't just ignore these distinctions.

Patreon Supporters:
Christoph Kovacs
David Johnston
Jason Killian
LoganMP
p11
Richard Penner
Rosario
Рекомендации по теме
Комментарии
Автор

You know something is useful when you can look at it from multiple perspectives.

caspermadlener
Автор

Geometric Algebras are quadradic rings and Clifford Algebras are a Big Red Dog.

pacotaco
Автор

Geometric algebra was a curiosity for a while. Guess I need to study it now.

curiousaboutscience
Автор

You are the only one that I found talking about that❤

santykachu
Автор

Something I've run into is that two different professors such as Professor Tisza and Professor Hestenes can refer to Geometric Algebra but they are not using the same notation. This is one reason why Professor Hestenes appropriated the name Geometric Algebra to distinguish his multivector formalism from Clifford Algebra. He wrote about this a lot. It involves concepts as well as notation because he is creating a unified system for both physics and math work.

BlueGiant
Автор

So in ypur book, we can talk about a geometric algebra over a finite field?

dwrchschr
Автор

So if they're not equal, they're at least isomorphic?

rtg_onefourtwoeightfiveseven
Автор

Glad you're finally addressing the allegations

justynpryce
Автор

The only difference I ever saw was in how people used the models they constructed from an algebra. Essentially an ontology layer... which isn't really the mathematics.

I've treated them as the same and only use one term over the other to keep the peace.

AlfredDiffer
Автор

I found your channel
Do you have any lessons on the topic?😊

TheDead-tg
Автор

Why do I see Cl(a, b) and G(a, b, c) or E(a, b, c) ?

dadsquadmusic
Автор

Ok. My understanding was that Clifford's algebra is subset cause there are more GAs

pavelperina