Uniform Continuity and Compactness

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Uniform Continuity and Compactness

In this video, I show a super nice property of uniform continuity: Namely any continuous function on [a,b] is *automatically* uniformly continuous. This test definitely saves us lots of time, enjoy!

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Bolzano–Weierstrass really be hitting different this time 4:35

alexischavoya
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Never saw anyone this excited about BWT

ativjoshi
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X_(N_K) - 1/N_K<Y_(N_K)<X_(N_K)+1/N_K
As K goes to infinity the first and last terms of the double inequality tends to x_0, the same must happen with Y_(N_K), no ?

josemarino
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Don't you like number theory? It is fascinating.

guill