How to Solve Radical Equations that have Three Radicals: Step-by-Step Explanation

[AlFahadOnlineAcademy]

Sir! you explained in an easy way, have cleared many things, hope you will keep it up. We "AL FAHAD EVENING ACADEMY" team thanks you by the deep of heart.

[touhami]

Sqrt(A)=sqrt(B)+sqrt(C)
Conditions :
B>=0, C>=0, A>= B+C ==> D: validity
Solve (A-B-C)^2= 4BC in D

[charlesmitchell]

This was too easy for you. I like it better when you solve the challenging geometry problems. But I like your videos in general. Thanks!

[peterta]

excellent ! I like this makes things simple five stars !

[jojella]

I think there exists a mistake moving to step 3 we must not cancel the √ with the exponent bcz the number under the redicle can be of a positive or a negative value but the answer of the (√3)² can't be negative so we have 2 cases of x at this step .. Idk this is what I've learnt 🙁😐

[fatin]

If i get two x ... Is that true?? Bcs i get kuadratic equation at the end🙏
This is for my math question

[damianmatma]

00:00 Why don't you start with calculating the Domain?
1) √(9x-2) ⇒ 9x-2 ≥ 0 ⇒ 9x ≥ 2 ⇒ x ≥ (2/9) ⇒ x ∈ [ (2/9) ; +∞] ⇒ x ∈ [ (8/36) ; +∞)
AND
2) √(4x-3) ⇒ 4x-3 ≥ 0 ⇒ 4x ≥ 3 ⇒ x ≥ (3/4) ⇒ x ∈ [ (3/4) ; +∞] ⇒ x ∈ [ (27/36) ; +∞)
AND
3) √( x+1) ⇒ x+1 ≥ 0 ⇒ x ≥ (-1) ⇒ x ∈ [ (-1) ; +∞)
which causes that the Domain is:
D: x ∈ [ (3/4) ; +∞)

07:04 So our solution "3" ∈ D

[tobyharnish]

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