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Find the value of `1+i^(2)+i^(4)+i^(6)+...+i^(2n),` where`i=sqrt-1` and nEN.
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Find the value of `1+i^(2)+i^(4)+i^(6)+...+i^(2n),` where`i=sqrt-1` and nEN.
1+i^2+i^4+i^6+ ….+i^2n is
Evaluate `1+i^2+i^4+i^6+...+i^(2n)dot`
i^2+i^4+i^6+ …. upto (2n +1) terms =
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