Evaluate `1+i^2+i^4+i^6+...+i^(2n)dot`

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This is the Solution of Question From RD SHARMA book of CLASS 11 CHAPTER COMPLEX NUMBERS AND QUADRATIC EQUATIONS This Question is also available in R S AGGARWAL book of CLASS 11 You can Find Solution of All Question From RD SHARMA and R S AGGARWAL book from class 6-12 on our app DOUBTNUT for Free

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==== QUESTION TEXT ====

Evaluate `1+i^2+i^4+i^6+...+i^(2n)dot`

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I thought that it is wrong because in this G.P., as we know, r = i^2 which is equal to i^2 = -1 and -1<1, so here we use another formula
Sn = a(

anjalijindal

Evaluate `1+i^2+i^4+i^6+...+i^(2n)dot`

Evaluate `1+i^2+i^4+i^6+...+i^(2n)dot`

1+i^2+i^4+i^6+ ….+i^2n is

RD Sharma Class 11 Exercise 13.1 Example number 04 | Evaluate 1+i^2+i^4+i^6+---+i^2n

Find the value of `1+i^(2)+i^(4)+i^(6)+...+i^(2n),` where`i=sqrt-1` and nEN.

i^2+i^4+i^6+ …. upto (2n +1) terms =

Evaluate: `(i^2+i^4+i^6+i^7)/(1+i^2+i^3)`

Find the values of the following expressions: \[ 1+i^{2}+i^{4}+i^{6}+i^{8}+\ldots+i^{20} \]

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