A-Level Maths: R4-12 Forces: Introducing Smooth Inclined Planes

[shay]

That is the most perfect theta I've ever seen

[kimran]

no other video explains this topic as well as you do, in my opinion. Thank you so much for your help. Truly grateful.

[latiku]

You have just saved me from my mechanics related breakdown and perfectly addressed my confusion with this- thank you so much!!

[saragarber]

Just wanted to say the way you explain any subject in maths, regardless the difficulty, it is alway in a thorough, clear manner! Thank you so much for sharing with us!

[xkl-physics]

This is a masterpiece, thanks so so much sir for putting this video up :)

[tianchongsun]

Its a crime that this video is underrated.

[DEEPAK-xycx]

This video cleared my doubt which was bugging me for several months

[milesaasher]

THANK YOU SO MUCH I REALLY NEEDED THIS THANK YOU S GAZILLION my face was like this 🥴 when I saw this for the first time in

[nerushankumar]

Hi, i was asking if its weird to be learning year 13 A-level content in year 12, because people from different schools are only learning as content this year.

[saile_]

does this also cover all the AS Physics inclined planes content?

[velona]

Excellent. Very well explained. Thank you so much.

[miguelsanchez-soyq]

Thank you sir for the explanations..I just found out the missing piece..

[dickmercs]

thank you sir you are an absolute legend

[disharai]

how did you derive mgcostheta from the angle theta

[nayyirrr]

Why do we have to resolve weight perp. and parallel to the slope and not like forces in a cartesian plane?

[humanNumer]

what I hate and don't get about the whole problem is not the calculations but the fact that physicists just made up the rule that the breakdown forces will break down exactly and proportionately to sides like in a right-angled triangle. It's like describing reality using just simple shapes or cute assumptions. Is there actually any measurable proof that the forces would break down like side lengths in triangle? Second annoying thing is that despite drawing two vectors into which the gravity breaks down, we only consider the one perpendicular to the surface as the normal reaction force? Let's imagine the slope being really super steap, would we still ignore the other vector? (or is this left to be introduced as friction later on?)

[eceozhan]

I"m watching this video to help me with A level physics