What is Momentum Class 9

What is Momentum Class 9. Let's look the Concept of Momentum in Physics in a Fun and Practical way!

In the context of physics, momentum refers to the quantity of motion an object has. It is a vector quantity, meaning it has both magnitude and direction. Mathematically, momentum (p) is defined as the product of an object's mass (m) and its velocity (v):

p = mv

Here's what these terms mean:
1. Mass (m): Mass is a measure of the amount of matter in an object. It is a scalar quantity and is usually measured in kilograms (kg).
2. Velocity (v): Velocity is the rate of change of an object's position with respect to time. It's a vector quantity that has both magnitude (speed) and direction. Velocity is usually measured in meters per second (m/s).

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[Anonymous-dkgh]

Hey, sir
I really like your teaching style you make physics so much interesting. I think if more & more teachers started teaching like you then India as a country will prosper!!!!

For the ❤ of

[mythreyeepinagadi]

Given,
s (height) = 15m
mass = 1 Kg
p=mv
P=1xv
using third law of motion....
v^2-u^2=2as
u=0, as coconut is initially at rest.
on substituting u=0, in third equation of
v^2-0=2x10x15 (on taking g=10m/s^2
v^2=300
v=√300
v=10√3
on substituting the values in
p=1x10√3
p=10√3 kgm/s(taking √3 = 1.732)
p=10x1.732
p=17.32 kgm/s
Therefore, the momentum of the falling coconut is 17.32 kgm/s.

[mewsicman]

Using kinematics,
First we calculate the time it takes for the coconut to reach the ground...
d = Vi (t) +1/2 (a)(t)²
15m = 0m/s(t) + 1/2(9.8m/s²)t²
Hence: t=√3 = 1.73

To calculate the final velocity we use:
Vf = Vi + (a)(t)
Vf = 0m/s + 9.8m/s²(1.73s)
Vf = 16.95 m/s

Finally, the momentum when it hits the ground is:
p = mv
p = (1kg)(16.95m/s)
p = 16.95 kg • m/s or 17 kg • m/s

Which I think is pretty dangerous especially if it hits you directly on your head 😂

[ibrahimnallamandu]

Initially the coconut was at rest so it's initial velocity 'u' will be zero. According to Newton's third equation of motion v^=u^+2as u=0 a=g= 9.8 m/s^ s=15m. v^=0+2×9.8×15 =294 so v=√294= 17.14 approx. Momentum =Mass × velocity. So P= 1kg×17.14 m/s. =17.14 kg.m/s

[sriritwikshastry]

Initially, the coconut was at rest so it's initial velocity 'u' will be zero.
u = 0
v= ?(Have to find out)
height / s = 15 m
a = 10m/s (Gravity Approx.)
Now by third equation of motion :-
v² - u² = 2as
v² = 2× 10 ×15 m²/s²
v² = √300m²/s²
v = 10√3 m/s = 10×1.73 = 17.3 m/s
Mass of coconut = 1 kg
Velocity of it during reaching the ground = 17.3 m/s

P = mv
Momentum = Mass x Velocity
1 kg × 17.3 m/s = 17kg m/s

=== So the momentum of the falling coconut is **17Kg m/s**.

Always love your videos sir🔥🔥! This was a nice one! A nice question too! hope my answer is right .

[shreybarot]

Thanks a lot sir you have help me to master the concepts of physics. Love you sir ❤

[pranavabalabaskar]

Sir, please start courses for 11th for physics, chemistry, and maths.... It will help us very much.
Concepts like Chemical Thermodynamics and Organic Chemistry is tough. It Will be Easy if you teach us sir.

[aravindnairh]

Sir, the location you are in .
(Samudra) Kovalam beach i visited the place.

[drrishimani]

You're the best teacher ever...
Thanks a lot!!

[kalimuthuperiyanayagi]

I started to watch your video.your teaching is awesome ❤️

[anushkasawant]

Hello Sir...quite a interesting question...Do we have to use v² = u² + 2gh?? If yes then by calculating we get....p = 17.3205080757 kg m/s

[AdityaKumar-iypu]

at the uppermost height
u = 0
v= ??
h= 15 m
g = 10m/s
Now by third equation of motion
v² - u² = 2gh
v² = 2× 10 ×15 m²/s²
v² = √300m²/s²
V = 10√3 m/s = 10×1.73 = 17.3 m/s
Mass of coconut = 1 kg
Velocity of it during reaching the ground = 17.3 m/s
Momentum = Mass × velocity
1 kg × 17.3 m/s = 17kg.m/s
So we clearly see that this is the sufficient amount of momentum to kill a person.

[saja]

Sir im from kerala and im a big fan of you. This video make me so happy😻

[dhanvipatel]

Thank you sir for your good explanation!

[malekthiek]

Thank you sir for nice explanation about momentum ♥️ your teaching style

[charansstudycorner]

Momentum is 17.32 kg m/s using the relation p2=2×m×ke. Taking g as 10 m/s2

[btseven]

Hi sir your videos are soo helpful thank u soo much 👋

[ethiostudent]

Wow I always watch you're videos, I appreciate you.
And I'm trying to response.thanks.

[mr.gbff]

Amazing but newton would have sat under coconut tree that would be good for us 🙃