Integration By Partial Fractions (distinct linear factors)

Calculus 2, integration of rational functions by partial fraction decomposition with distinct linear factors.

0:00 integral of 1/(4-x^2)
4:32 integral of (5x-13)/(2x^2+5x-3)
9:39 Integral of a rational function with 3 distinct linear factors

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[beetlepimp]

loved the quick way to find A, B, and C. this was the most confusing part for me but you made it easier!

[mathevengers]

Waiting for a blooper video. They are my favorite because they show hard work behind a small video.

[kavyagupta]

My school teacher didn't explain it well, so I came here...and guess what...I'm going back with a new method of integration....
Thanks a lot...

[joshuadiedrich]

Thank you! Working hard to pass Calculus 2. You remind me of my old math tutor… Very happy to have you!

[wuyqrbt]

First!
I like your way for factor trinomial, Great.
Now, I'm waiting for your next one.
Thank you

[abhi_kr_mishra]

The legendary teacher mr. BPRP is here to teach partial fraction.

[sudoheckbegula]

4: 31
Did he forget to cut the video?

[anshumanagrawal]

I personally feel this sort of method is very artificial, in fact because of this, I've had disagreements with my teacher. I prefer a more natural approach to Partial fractions, instead of writing the fraction as a sum of multiple fractions with unknowns, I try to get their without any hand waving, like 1/(4-x^2) = 1/(2-x)(2+x) = [(2-x)+(2+x)]\4[(2-x)(2+x)]