Solving a Quick and Easy Functional Equation

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One of the few questions that I knew how to solve before watching your solution! And the reason I knew how to solve this type of equation is bc one time I struggled so badly when I was tutoring someone in precalc back in my college days! I would never forget about this type of equations! : )

blackpenredpen
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The first idea that comes to my mind is exactly this substitution because it is a common way to solve the integrals involving this denominator.
Keep up your good work!

yvonne
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A method that makes complicated matters easier, I also use this wonderful way.

vkbteco
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It must be said that f is determined only for t>0.

sppwqsr
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love how you tackle these challenging problems, appreciate your expertise

math
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Congrats on 8k subscribers!!!
Such unique questions on here, it's incredible

MathElite
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I once saw in another YouTube video that if the functional equation is of the form f(g(x))=h(x), then the solution is h(g^-1(x)), which is easy to proof. Essentially that what you did on the video, but to have it written out as an identity helps more than what one may think.

luxel
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Put x= sinh(t). Then you will get f(e^t)= sinht /(sinht +1). On simplification you will get f(e^t) =(e^t - e^-t) /(e^t - e^-t +2). Replacing e^t by x, you get f(x).

prabu
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In 1st step t = x + √(x²+1) and x=(t² - 1)/2t
In last step t = x
How?!

rotten-Z
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Youtube algoritması sağolsun bu güzel video ile tanışmama vesile oldu. Video için teşekkürler.

grozaiv
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An even simpler method (assuming you're familiar with hyperbolic functions):
Let x=sinh(y)
=>
=>
=> . Let u=e^y
=> f(u) = (u^2-1)/(2u+u^2-1)
=> f(x) = (x^2-1)/(2x+x^2-1)

monkeyonaspacerock
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Another way to do it is by noticing that t = e^(sinh^-1(x))

So we have x = sinh( lnt )

But what you did is better

joaquingutierrez
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Probably one of the easiest questions exploiting the nature of functions. Love your video and pls keep posting more :)

VSN
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Substitution all the wayyy. Amazing as always !

cryfan
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Another great explanation, SyberMath!

carloshuertas
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I saw that if you plug in zero in the functional equation that this results into f(1)=0. A good check for the final function.

ernestschoenmakers
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We can solve by using trigonometric substitution. Consider a triangle with side lengths equal to 1, x and sqrt(x^2 +1). So the function becomes for the angle t. Then,

fatihsinanesen
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wow, you have widened my horizon, thanks a lot!

elifotosfer
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When I become a math teacher, I will give this problem to my students

jofx
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Super video Syber, thank you! I think I learned a nice trick with this video 😁 Please, do more videos with this kind of problems!

ermattia