SAT Math Algebra 1

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I found the inverse of 3x (which is x/3), then I plugged that into f(3x). This gave me f(x). So then I substituted the 6 into f(x) which gave me the same answer. This could work for any value like trying to find f(9) or f(13), etc.

thegolemguardian
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You could also just change x - 6 to (x/3) - 6 so that it turns f(3x) to f(x) and substitute 6 to f(x), which will be (6/3) - 6 = -4

cloroxbleach
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This channel should get more subscribe!

photonch
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That is a better explanation than my math teacher did

getachewh
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F of 6 is therefore a product of which would relate to (3x2)given is 3 therefore f of 6 is -4, the final solution . This teacher intrigues me so, I am document every problem that makes me think in a possible way . I will be 75 on July 27, education and math still intrigues me !!😮

trevinog
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3x = y => x= y/3

Substituting,
f(y) = (y/3) - 6

Putting y = 6
f(6) = 6/3 - 6 = -4

AchaJi-ih
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Thanks a lot this actually helped me quite a bit ❤

HelloBye-ufur
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Or, you could start by finding what f(x) is from f(3x), thus, taking z = 3x => f(z) = z/3 - 6, or (fx) = x/3 - 6 if you want it.
In the end, f(6) = 6/3 - 6 = -4

bytemark
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This is an great learning exercise! Excellent

zahariastoianovici
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When a teacher is good, subjects are fun !!

nk
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f(3x)=x-6

f(x)=x/3-6
f(6)=6/3-6
=-4#
如果要把數字代進方程裏
必須找出「一個變數」的
方程式才把這數字代這一
個變數代進去!!😅😅

Aulkk
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This is the function we know, but still, your videos explain it wonderfully, even though I am Turkish.

yasaryaralp
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you can aalso divide every x term by 3 so f(x) will be x/3 - 6 then you can plug in the 6 you will get -4 still

skewer
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Sir you explain it very well
Thanks keep uploading such videos

DIVYAMMISHRA-tefi
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Could you cover tougher problems in upcoming videos please? Thank you!

manansharma
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oh that's more direct than how i did it. I found that f(x)=x/3-6 by plugging in the inverse function of 3x into f(3x). then i just evaluated f(6)

lumina_
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It's much clearer to note that 3x=6.
Therefore x = 6/3, so x = 2
Then substitute.

davidbroadfoot
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Wow, you made it simple to understand. Thank you.

seventhunder
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Thx again and again and again, Mr. H ❤

marcelhayong
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Put some more videos on Functions, Modulas function, Inequalities Questions and related topics, it helps a lot in revising these topics ❤, thanks. 😊

RonnyS.