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Factorize : `(x-2y)^3+(2y-3z)^3+(3z-x)^3`

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Factorize : `(x-2y)^3+(2y-3z)^3+(3z-x)^3`
Factorize : `(x-2y)^3+(2y-3z)^3+(3z-x)^3`
Without finding the cubes, factorise (x-2 y)^3+(2 y-3 z)^3+(3 z-x)^3 W
Using a+b+c = 0 Then a³+b³+c³ =3abc. Factorise :(x-2y)³+(2y-3z)³+(3z-x)³
Factorise (x-2y)³+(2y-3z)³+(3z-x)³
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