[Discrete Mathematics] Divisibility Examples

preview_player
Показать описание
We do proofs with divisibility in this video.

LIKE AND SHARE THE VIDEO IF IT HELPED!

*--Playlists--*

*--Recommended Textbooks--*

Hello, welcome to TheTrevTutor. I'm here to help you learn your college courses in an easy, efficient manner. If you like what you see, feel free to subscribe and follow me for updates. If you have any questions, leave them below. I try to answer as many questions as possible. If something isn't quite clear or needs more explanation, I can easily make additional videos to satisfy your need for knowledge and understanding.
Рекомендации по теме
Комментарии
Автор

In the last example, shouldn't it be either 8(k+1)j or 8kj (instead of 8kjk)?

arieppy
Автор

On the Example where 8(k+1)k is divisible. How did you arrive to that? is it because k*k+1 will always equal an integer therefore it can be divided because of a=dq+r?

migs_dotcom
Автор

Where does the 8|(n²-1) come from? Is that not supposed to be 4|(n²-1)? The pinkish part at the end is a bit unclear.

thepedzed
Автор

Could you explain a bit further why dividing with 1 causes problem?(related to the first problem)

Because the problem said A|B or A|C, now both doesnt have to be divisible so that you can get A = 6, B = 6 and C = 1. Then you will get A|BC with following A|B.

Anyways thanks a lot for making and posting these videos, have an exam in 2 days. Im a poor student but I have mentioned this channel to my math class on many occasions :)

Andersl
Автор

Also wondering why you replaced n with (2k+1).

joshuaschwarting
Автор

In the last example, how do we know that atleast one of them is even and the other one is odd ?

SALMalikk
Автор

I am so confused by this. What if n = 1? That means that this is saying 4 divides 0.

rkcst
Автор

Oh my goodness we both used the same counterexample in problem 1

jidelgado
Автор

then how did u show in ur first lecture that a|b, a|c then a|(b+c)....but in ur ex u r telling that 6|6 which is not valid then ur first prove was wrong.

AdityaKumar-rkrq