Buffer solution pH calculations | Chemistry | Khan Academy

Example of calculating the pH of solution that is 1.00 M acetic acid and 1.00 M sodium acetate using ICE table. Another example of calculating pH of a solution that is 0.15 M ammonia and 0.35 M ammonium nitrate.

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[MynameisJapan]

Advice: make sure you have a Ka value. My textbook gave me an intial Kb value and I spent 45 minutes trying to figure out what was wrong. Remember, you can convert Ka to Kb with the expression Ka * Kb =1.0E-14
then simply take the negative log to get Pka!
Cheers!

[noahsalomons]

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[yx_png]

I had SO many question about Henderson-Hasselbalch equation before I watch this vedio.
Thanks a lot. This vedio is really helpful.

[rofhiwalivingstone]

OMG this is the first time doing biochemistry and people who did it before me kept on saying the calculations part, specifically buffers are hard. Clearly they haven't seen your videos. I love how you work out the questions, the way you explain.. THANK YOU FOR HELPING US.

[nicaalyssashanearauag]

Youtube is my new teacher, thanks a lot!!!!

[psyp]

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[graceloussakou]

So so helpful! thanks, now I don't need to wait for an office appointement with my Biochem professor. Gosh I love our the 21century!

[farhansadikabtahifh-]

Thanks a lot.You Will be always in my heart

[alessandrac]

Much appreciated. It was a very comprehensive tutorial. In my class i don't have lectures.. it's all from the textbook so i rely on vids like this to get me through

[johnguillen]

I get the equation and sometimes get the right answer but I really never understood what is actually happening until I watched your video. Thank you

[wafasaliha]

thank you so much it's so helpful I wish u r my teacher

[puretwr]

Khan academy is the best of chemistry in my heart. 👏🏼

[wildzach]

"Let's say we already know the Ka..."
*My professor laughs maniacally*

[aishan.]

For the first time in forever my concepts become crystal clear!

[NCBrianS]

Im having a hard time between knowing when to do it this way vs using the common ion and ICE method as both problems seem pretty similar at first in terms of approach. Any advice?

[mahmoudemadeddin]

for this question 2:54
why all of this
just go with moles and add them to the base and remove from the acid, more easier!
pH = 9.25 + lg (0.12+0.005 / 0.1 - 0.005 ) = 9.369

[torchlight]

Good explanation but how can you come up with the chemical equation? I'm having a hard time creating the equation hELP

[RickRudy]

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[sarahfaress]

I get why you divided the 0.05 molNaOH/0.50L to find the molarity, but why is the same not done for the buffer componenets? we have only 0.50 L of solution, so shouldn't the concentration of NH3 be 0.50 L(0.24mol)/1L ? and then add to it the 0.01M of NaOH?

[sara-kfvh]

4:25 why does it go to completion? not equilibrium