Find the pH of a Buffer after adding NaOH

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Adding NaOH *increases* the amount of conjugate base in the buffer solution, and also *decreases* the amount of weak acid. This affects the "base over acid" part of the Henderson-Hasselbalch equation ... the part that is Log'ed. So adding a small amount of NaOH will increase the pH of the solution, but not by much.

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So when adding bases yo add it to the base in the log and reduce that number from the acid, the opposite for adding acids is the same

bumxrr
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Great video! Right when I needed this specific type of question for help :)

reader_dragon
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If we were to add HCl, would we be adding the moles to the weak acid and subtracting from the conjugate base?

ahgazenity.aliverse
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My lecturer has a very long method of doing a problem like the one in this video. Will i still get full marks if i follow your method instead? :)

motivationalheroes
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If you add 1 mL of a solution do you need to re calculate your concentration of conjugate acid and base

kanemorisaki
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Wouldn't you have to find the moles of the acid and base and then subtract the 0.001 from that and then recalculate the concentrations?

oscarcolin
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What happens when the concentration of the added sodium hydroxide is much higher than the the acid

winstonmudolo
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Thank you!! but what would happen when you add something like 2M NaOH? do you still take moles or in terms of concentration for the henderson's eqn?

localsleepdeprivedmonkey
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how do you do this if not given the pka?

ARTDEVGRU
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Lmfao!!!! I can tell you just learned that and wanted to use it!!!;)

michaelworrell