|#2^a+4^b+8^c=328 - |# find the ordered pair (a,b,c)| |#olympiad||#tricks||@Maths with shimna|

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if a,b,c are natural numbers , then find the ordered pair (a,b,c)

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Hi all,
In today's session we will solve if a,b,c are natural numbers , then find the ordered pair (a,b,c)

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#2^a+4^b+8^c=328
# findx
#olympiad
#exponents
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