Prove that 2nCn = (2^n {1⋅3⋅5⋅7…(2n-1)})/n!

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Class XI_Permutations & Combinations
Q: Prove that 2nCn = (𝟐^𝒏 {𝟏⋅𝟑⋅𝟓⋅𝟕…(𝟐𝒏−𝟏)})/𝒏!

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